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dem82 [27]
3 years ago
6

Find the equation of the axis of symmetry of the following parabola algebraically. y=2x^2+16.

Mathematics
1 answer:
Inessa05 [86]3 years ago
3 0

Answer:

x = 0

axis of symmbery = -b/2a or x vertex on quadratic equation

0/4=0

x=0

Step-by-step explanation:

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