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Lilit [14]
3 years ago
14

-5 ≤ -2; Add 7 to both sides Help pls

Mathematics
1 answer:
kipiarov [429]3 years ago
3 0

Answer:

-5 + 7 <u><  </u>-2 + 7

2 <u><</u> 5

Step-by-step explanation:

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Can i get some help :
Charra [1.4K]

Answer:

b = \frac{7}{12}

Step-by-step explanation:

b + \frac{2}{3} = 1 \frac{1}{4} ← change to an improper fraction

b + \frac{2}{3} = \frac{5}{4}

Multiply through by 12 ( the LCM of 3 and 4 ) to clear the fractions

12b + 8 = 15 ( subtract 8 from both sides )

12b = 7 ( divide both sides by 12 )

b = \frac{7}{12}

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3 years ago
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According to the picture, which of the following is true?
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Answer:

B is the answer for but I don't now about others thank you

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3 years ago
$2.95+$3.09+$5.85+$4.10
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Step-by-step explanation:

the value of P(B|A)P(B∣A), rounding to the nearest thousandth

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3 years ago
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A store is selling 5 types of hard candies: cherry, strawberry, orange, lemon and pineapple. How many ways are there to choose:(
Volgvan

Answer:

The number of ways of selecting of n items form r different items =^{(n+r-1)}C_{(r-1)}

A store is selling 5 types of hard candies: cherry, strawberry, orange, lemon and pineapple.

A) How many ways are there to choose 32 candies?

So, n = no. of items = 32

r = no. of types of items = 5

So, No. of ways to choose 32 candies = ^{(32+5-1)}C_{(5-1)}

                                                               = ^{36}C_{4}

                                                                 = \frac{36!}{4!(36-4)!}

                                                                 = 58905

So, No. of ways to choose 32 candies is 58905

B)32 candies with at least a piece of each flavor?

Out of 32 you choose 5 candies of different types

So, Remaining candies = 32 - 5 = 27

So, No. of ways to choose 27 candies = ^{(27+5-1)}C_{(5-1)}

                                                               = ^{31}C_{4}

                                                                 = \frac{31!}{4!(31-4)!}

                                                                 = 31465

So, No. of ways to choose 32 candies with at least a piece of each flavor is 31465

C) 32 candies with at least 4 cherry and at least 6 lemon?

So, you already choose 6+4= 10

So, remaining candies = 32-10 = 22

So, No. of ways to choose 22 candies = ^{(22+5-1)}C_{(5-1)}

                                                               = ^{26}C_{4}

                                                                 = \frac{26!}{4!(26-4)!}

                                                                 = 14950

Hence No. of ways to choose 32 candies with at least 4 cherry and at least 6 lemon is 14950

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4 years ago
Which equation can be used to find the area of the parrellogram shown
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Area=basexheight

Area=9x4

Area=36
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3 years ago
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