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slega [8]
3 years ago
5

Graph each quadratic equation using a table of values. Identify all key characteristics.

Mathematics
1 answer:
adoni [48]3 years ago
5 0

Answer:

See graph below

Step-by-step explanation:

The domain is (-∞,∞) and the range is [1,∞)

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The percent of decrease would be 60%
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Volume of a can 12cm x 8 cm
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3619.11 or <span>2412.74 ...............</span>
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Primitive function for:<br><br> 1. f(x)=4e2x+e−x, sådan att F(0)=2
Free_Kalibri [48]

The primitive function for f(x) = 4e^{2x} + e^{-x} is given by it's indefinite integral.

To calculate it, recall:

\frac{d}{dx}e^{ax}=ae^{ax}

\int c f(x)dx = c\int f(x)dx

Let's begin

\int 4e^{2x}+e^{-x}dx \\4\int e^{2x}dx+ \int e^{-x}dx\\4\frac{e^{2x}}{2}+\frac{e^{-x}}{-1}  + c\\

F(x) = 2e^{2x}-e^{-x} +c

To find the costant, we just need to use the fact that F(0)=2

F(0) = 2 \\4e^{0}+e^{0} + c =2\\5+c =2\\c=-3

Therefore,

\boxed{F(x) = 2e^{2x} - e^{-x} -3 }

6 0
3 years ago
What is the value of 2 1/5 +3 4/5=
navik [9.2K]

Answer:

6

Step-by-step explanation:

I like to line up my addition problems vertically

2  1/5

+ 3 4/5

--------------

5 5/5

but 5/5 = 1

5 + 1

6

5 0
3 years ago
Total world consumption of iron was approximately 900 million tons in 1993. If consumption had increased by 2.5% each year and t
Lilit [14]

Step-by-step explanation:

We can model the annual consumption of iron by the equation

c = 900 million tons x 1.025^n, where

n is the number of years after 1993 and

c is the consumption for that year.

An estimate for the total consumption of iron can now be obtained by integrating this equation with respect to a dummy variable, x from 0 to n.

C = 900*10^6* \int\limits^n_0 {1.025^x} \, dx

This equation simplifies to

C = 900 million tons x (1.025^n - 1) / ln(1.025), where

x is a dummy variable and

C is the total consumption of iron n years after 1993.

Let R be the amount of iron remaining at n years after 1993, so

R = 480 billion tons - C

R = 480 billion tons - 900 million tons x (1.025^n - 1) / ln(1.025)

We need to find the value of n when R is 0, so

0 = 480 billion tons - 900 million tons x (1.025^n - 1) / ln(1.025)

Simplify this equation to obtain

n = 107.4

So the iron will run out in the year 1993 + 107 = 2100

6 0
2 years ago
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