The point-slope equation is
m, the slope is -4/5
We plug in the point (3,-2) to find b:
We can now plug in b to the equation:
Answer:
E(X) = 1.5
Var(X) = 2.325
Step-by-step explanation:
X - the number of pairs of cats (out of the 5 cats) to choose the same type of treat, can take values of:
X = (0, 1, 2, 3, 4, 5)
Also probability of choosing a treat, since they are all equally likely is: f(x) = 1/10
E(X) - expectation of x, is given by:
E(X) = Summation [X*f(x)]
E(X) = 0x(1/10) + 1x(1/10) + 2x(1/10) + 3x(1/10) + 4x(1/10) + 5x(1/10)
= (1/10) x (1+2+3+4+5)
E(X) = 3/2 = 1.5
Also, variance is:
Var(X) = Summation f(x)*[X - E(X)]^2
= (1/10)x(0-1.5)^2 + (1/10)x(1-1.5)^2 +(1/10)x(2-1.5)^2 +(1/10)x(3-1.5)^2 +(1/10)x(4-1.5)^2 +(1/10)x(5-1.5)^2
= (1/10)x[2.25 + 0.25 + 2.25 + 6.25 + 12.25]
Var(X) = 2.325
Answer:
46, 55
Step-by-step explanation:
Please let me know if you want me to add an explanation as to why this is the answer. I can definitely do that, I just don’t want to waste my time in case you don’t want me to :)
Answer:
Step-by-step explanation:
Since each trial is independent of the other
no of mistakes he does is binomial with p = 1/3
a) the probability that he makes no mistakes on his first 10 orders but the 11th order is a mistake
=
b) Prob that shanker quits = P(Shankar does I one mistake and Fran does not do the first one)+Prob (Shanker does mistake in the II one while Fran does both right)
=
Using the normal distribution, it is found that there are 68 students with scores between 72 and 82.
<h3>Normal Probability Distribution</h3>
The z-score of a measure X of a normally distributed variable with mean and standard deviation is given by:
- The z-score measures how many standard deviations the measure is above or below the mean.
- Looking at the z-score table, the p-value associated with this z-score is found, which is the percentile of X.
In this problem, the mean and the standard deviation are given, respectively, by:
The proportion of students with scores between 72 and 82 is the <u>p-value of Z when X = 82 subtracted by the p-value of Z when X = 72</u>.
X = 82:
Z = 1
Z = 1 has a p-value of 0.84.
X = 72:
Z = 0
Z = 0 has a p-value of 0.5.
0.84 - 0.5 = 0.34.
Out of 200 students, the number is given by:
0.34 x 200 = 68 students with scores between 72 and 82.
More can be learned about the normal distribution at brainly.com/question/24663213
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