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a_sh-v [17]
4 years ago
11

What is the equation of the graphed line in the point-slope form?

Mathematics
1 answer:
Softa [21]4 years ago
5 0
Answer: A) y+6=3/4(x+4)

Once this equation is simplified, it becomes y=3/4x-3, which is the equation of the line.
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Write an expression that can be used to find
Aleksandr [31]

Answer:

(4×200)+(2×70)+(4×5)

Step-by-step explanation:


8 0
4 years ago
All answers please(ALL)
astraxan [27]

A.13

B. 35

C. -6

D. -3

E. -1

F. -.75

Solve for the equation or problem.

A. 8

B. 4

C. 1

Add together al variable terms with the same variables.

1. -4x+10

2. 21t-10s+5r-10

Hope this helps!

6 0
4 years ago
The width of a rectangle is 9 in. shorter than its length. The area of the rectangle is 252 in². What is the length of the recta
erastovalidia [21]

Answer:

the length of the rectangle is, 21 in.

Step-by-step explanation:

Area of the rectangle(A) is given by:

A=lw           .....[1]

where,

l is the length of the rectangle

w is the width of the rectangle.

As per the statement:

The width of a rectangle is 9 in. shorter than its length.

⇒w = l-9

It is also given that:

The area of the rectangle is 252 in².

⇒A = 252  in².

Substitute in [1] we have;

252 = l(l-9)

⇒252 = l^2-9l

⇒l^2-9l -252 = 0

Factorize this equation:

Split the middle term;

⇒l^2-21l+12l-252=0

⇒l(l-21)+12(l-21)=0

⇒(l-21)(l+12)=0

By zero product property we have;

l-21 =0 and l+12 =0

⇒l = 21 and l = -12

Since, length cannot be in negative

⇒l = 21 in.

Therefore, the length of the rectangle is, 21 inches.

4 0
3 years ago
A model of a plane is made using a scale of 1:5. If the wings of the model are 1.2m long, what is the actual length of the wings
7nadin3 [17]

Answer:

  6 m

Step-by-step explanation:

Multiply your scale by 1.2 m:

  1 : 5 = 1.2 m : 6.0 m

The wings on the plane are 6.0 m long.

3 0
4 years ago
Write the equation of the line that passes through the point (–6, 2) and is parallel to the line whose equation is x = –10, then
vladimir1956 [14]
The gradient of the second line is zero since parallel lines have equal gradients;
y=0x+c
Replacing for x and y;
2=c
y=2


8 0
4 years ago
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