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3 years ago

8

The growth of an apple tree was measured. The tree grew 15 inches per year.

1 answer:

pogonyaev3 years ago

8 0

Answer:

1.04 mill

Step-by-step explanation:

15 inches to mill = 381

$365\sqrt{381}$ = 1.04 ( rounded )

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Abir walks four twelfths of a mile to school. Nadia walks two twelfths of a mile to school. How much farther does Abir walk than

exis [7]

Answer:

Step-by-step explanation:

four twelfths minus two twelfths equals two twelfths

4 0

3 years ago

A pyramid has a square base of length 8cm and a total surface area of 144cm². Find the volume of the pyramid. (Please use Pythag

Sveta_85 [38]

Answer:

$\displaystyle V_{ \text{pyramid}}= 64 \: {cm}^{3}$

Step-by-step explanation:

we are given surface area and the length of the square base

we want to figure out the Volume

to do so

we need to figure out slant length first

recall the formula of surface area

$\displaystyle A_{\text{surface}}=B+\dfrac{1}{2}\times P \times s$

where B stands for Base area

and P for Base Parimeter

so

$\sf\displaystyle \: 144=(8 \times 8)+\dfrac{1}{2}\times (8 \times 4) \times s$

now we need our algebraic skills to figure out s

simplify parentheses:

$\sf\displaystyle \: 64+\dfrac{1}{2}\times32\times s = 144$

reduce fraction:

$\sf\displaystyle \: 64+\dfrac{1}{ \cancel{ \: 2}}\times \cancel{32} \: ^{16} \times s = 144 \\ 64 + 16 \times s = 144$

simplify multiplication:

$\displaystyle \: 16s + 64 = 144$

cancel 64 from both sides;

$\displaystyle \: 16s = 80$

divide both sides by 16:

$\displaystyle \: \therefore \: s = 5$

now we'll use Pythagoras theorem to figure out height

according to the theorem

$\displaystyle \: {h}^{2} + (\frac{l}{2} {)}^{2} = {s}^{2}$

substitute the value of l and s:

$\displaystyle \: {h}^{2} + (\frac{8}{2} {)}^{2} = {5}^{2}$

simplify parentheses:

$\displaystyle \: {h}^{2} + (4 {)}^{2} = {5}^{2}$

simplify squares:

$\displaystyle \: {h}^{2} + 16 = 25$

cancel 16 from both sides:

$\displaystyle \: {h}^{2} = 9$

square root both sides:

$\displaystyle \: \therefore \: {h}^{} = 3$

recall the formula of a square pyramid

$\displaystyle V_{pyramid}=\dfrac{1}{3}\times A\times h$

where A stands for Base area (l²)

substitute the value of h and l:

$\sf\displaystyle V_{ \text{pyramid}}=\dfrac{1}{3}\times \{8 \times 8 \}\times 3$

simplify multiplication:

$\sf\displaystyle V_{ \text{pyramid}}=\dfrac{1}{3}\times 64\times 3$

reduce fraction:

$\sf\displaystyle V_{ \text{pyramid}}=\dfrac{1}{ \cancel{ 3 \: }}\times 64\times \cancel{ \: 3}$

hence,

$\sf\displaystyle V_{ \text{pyramid}}= 64 \: {cm}^{3}$

8 0

3 years ago

2 1/4 r= 10<br> A. r = 4 1/3<br> B. r = 4 2/5<br> C. r = 4 4/9

max2010maxim [7]

Here, 2 1/4 r = 10
9/4 r = 10
r = 10*4 /9
r = 40 / 9
r = 4 4/9

In short, Your Answer would be Option C

Hope this helps!

8 0

3 years ago

Consider this three digit sequence 943. Is the first digit the largest or the second digit the smallest, and, is the third digit

maw [93]

Well, 9 is the largest, but 4 is the smallest and 3 is the second odd number. So it would go yes, no, no or if it's just one question, it would be no.

3 0

3 years ago

Dy/dx = y/x , y(1) = −2

s2008m [1.1K]

Start with

$\dfrac{dy}{dx}=\dfrac{y}{x}$

Separate the variables:

$\dfrac{dy}{y} = \dfrac{dx}{x}$

Integrate both parts:

$\displaystyle \int \dfrac{dy}{y} = \int\dfrac{dx}{x}$

Which implies

$\log(y) = \log(x)+c$

Solving for y:

$y = e^{\log(x)+c} = e^{\log(x)}e^c=xe^c$

Since $e^c$ is itself a constant, let's rename it $c_1$ .

Fix the additive constant imposing the condition:

$y(1) = c_1\cdot 1 = -2\iff c_1=-2$

So, the solution is

$y(x) = -2x$

5 0

3 years ago