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sertanlavr [38]
3 years ago
6

WILL MARK BRAINLIEST!! Just help me out with number 2 please. :)

Mathematics
1 answer:
marysya [2.9K]3 years ago
8 0

9514 1404 393

Answer:

  -5 is included in the solution set of the first, but not the second

Step-by-step explanation:

The solution to -2 ≥ 10 is x ≤ -5. The solution to -2x > 10 is x < -5. The difference is that x = -5 is included in the solution set of the first inequality, but is not included in the solution set of the second inequality.

When plotted on a number line, the former inequality has a solid dot at -5, indicating that point is included. The latter inequality has an open dot (circle) at -5, indicating that point is not included. (Both plots are shaded to the left of the dot.)

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Evaluate 1/2(4^3-6*3^2)
tatiyna
The answer is 5

1/2(4^3-6•3^2)
1/2(64-6•3^2)
1/2(64-6•9)
1/2(64-54)
1/2(10)
=5

Hope this helps! May I please have brainliest? tysm
7 0
3 years ago
Find the volume of a right circular cone that has a height of 9.6m and a base with a diameter of 2.9m. Round your answer to the
Vlad [161]

Answer:

r = \frac{D}{2}= \frac{2.9m}{2}= 1.45 m

If we convert the height to meters like this:

h = 9.6 cm *\frac{1m}{100 cm}= 0.096m

And we want to find the volume of the cone and is given by:

V = \pi r^2 h

And replacing we got:

V = \pi (1.45m)^2 (0.096m) =0.634 m^3 \approx 0.6 m^3

Step-by-step explanation:

For this case we have a right circular cone with a height of 9.6cm and a base with a diameter of 2.9m. We can find the radius like this:

r = \frac{D}{2}= \frac{2.9m}{2}= 1.45 m

If we convert the height to meters like this:

h = 9.6 cm *\frac{1m}{100 cm}= 0.096m

And we want to find the volume of the cone and is given by:

V = \pi r^2 h

And replacing we got:

V = \pi (1.45m)^2 (0.096m) =0.634 m^3 \approx 0.6 m^3

4 0
3 years ago
SOLVE OR SIMPLIFY THIS!! -6-(2x+7)=-2(x+6)-1
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\\ \sf\longmapsto -6-(2x+7)=-2(x+6)-1

\\ \sf\longmapsto -6-2x-7=-2x-12-1

\\ \sf\longmapsto -2x-13=-2x-13

\\ \sf\longmapsto 2x-2x=0

\\ \sf\longmapsto 0

3 0
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<em>There are 6,720 five digit numbers that can be formed from the digits provided given that no digit may be repeated.</em>

<em>Hope that helped!</em>

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The first number is 34 and the second number is 63
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