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sertanlavr [38]
3 years ago
6

WILL MARK BRAINLIEST!! Just help me out with number 2 please. :)

Mathematics
1 answer:
marysya [2.9K]3 years ago
8 0

9514 1404 393

Answer:

  -5 is included in the solution set of the first, but not the second

Step-by-step explanation:

The solution to -2 ≥ 10 is x ≤ -5. The solution to -2x > 10 is x < -5. The difference is that x = -5 is included in the solution set of the first inequality, but is not included in the solution set of the second inequality.

When plotted on a number line, the former inequality has a solid dot at -5, indicating that point is included. The latter inequality has an open dot (circle) at -5, indicating that point is not included. (Both plots are shaded to the left of the dot.)

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<u>Annotation</u>
General formula for distance-time-velocity relationship is as following
d = v × t
The velocity of the first car will be v₁, the time is 2 hours, the distance will be d₁.
The velocity of the second car will be v₂, the time is 2 hours, the distance will be d₂.


One of them traveling 5 miles per hour faster than the others. That means the velocity of the first car is 5 miles per hour more than the velocity of the second car.
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The distance of the two cars after two hours will be 262 miles apart. Because they go to opposite direction, we could write it as below.
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Plug the d-v-t relationship to the second equation
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v₁ × t + v₂ × t = 262
v₁ × 2 + v₂ × 2 = 262
2v₁ + 2v₂ = 262

Plug the v₁ as  (v₂+5) from the first equation
2v₁ + 2v₂ = 262
2(v₂ + 5) + 2v₂ = 262
2v₂ + 10 + 2v₂ = 262
4v₂ + 10 = 262
4v₂ = 252
v₂ = 252/4
v₂ = 63
The second car is 63 mph fast.

Find the velocity of the first car, use the first equation
v₁ = v₂ + 5
v₁ = 63 + 5
v₁ = 68
The first car is 68 mph fast.

Answer
\boxed{\boxed{ v_{1}=68mph} }
\boxed{\boxed{ v_{2}=63mph} }
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