Question

Please help i am stuck and trying not to fail lol. also if you can show work pls

Answer 1

Given:

The figure of rectangle.

To find:

a. The diagonal of the rectangle.

b. The area of the rectangle.

c. perimeter of the rectangle.

Solution:

(a)

In a right angle triangle,

$\sin \theta=\dfrac{Perpendicular}{Hypotenuse}$

$\sin 30=\dfrac{12}{Hypotenuse}$

$\dfrac{1}{2}=\dfrac{12}{Hypotenuse}$

$Hypotenuse=12\times 2$

$Hypotenuse=24$

So, the diagonal of the of the rectangle is 24 units.

(b)

In a right angle triangle,

$\tan \theta=\dfrac{Perpendicular}{Base}$

$\tan 30=\dfrac{12}{Base}$

$\dfrac{1}{\sqrt{3}}=\dfrac{12}{Base}$

$Base=12\sqrt{3}$

Length of the rectangle is 12 and width of the rectangle is $12\sqrt{3}$. So, the area of the rectangle is:

$Area=length \times width$

$Area=12 \times 12\sqrt{3}$

$Area=144\sqrt{3}$

So, the area of the rectangle is $144\sqrt{3}$ sq. units.

(c)

Perimeter of the rectangle is:

$P=2(length+width)$

$P=2(12+12\sqrt{3})$

$P=24+24\sqrt{3}$

$P\approx 65.57$

Therefore, the perimeter of the rectangle is about 65.57 units.