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3 years ago

ALL 4 ways of displaying a relation.

1 answer:

8 0

Domain:The set of the first numbers of the ordered pair.
Range:The set of second numbers of the ordered pairs.
Independent:The value of a variable that determines the output.
Dependent:

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PLEASE HELP!! This is due in less than 5 minutes or I fail!!!

Pepsi [2]

Answer:

A/ I think

The first one on the top

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3 years ago

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Divide 250 in the ratio of 1 : 4

Aleksandr [31]

1 + 4 = 5 (5 parts)
£250/5 = 50 
1 x £50 = 50 
4 x £50 = 200 
so the answer is 50:200

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3 years ago

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A metal cylinder can with an open top and closed bottom is to have volume 4 cubic feet. Approximate the dimensions that require

Aleksandr-060686 [28]

Answer:

$r\approx 1.084\ feet$

$h\approx 1.084\ feet$

$\displaystyle A=11.07\ ft^2$

Step-by-step explanation:

Optimizing With Derivatives

The procedure to optimize a function (find its maximum or minimum) consists in :

Produce a function which depends on only one variable
Compute the first derivative and set it equal to 0
Find the values for the variable, called critical points
Compute the second derivative
Evaluate the second derivative in the critical points. If it results positive, the critical point is a minimum, if it's negative, the critical point is a maximum

We know a cylinder has a volume of 4 $ft^3$ . The volume of a cylinder is given by

$\displaystyle V=\pi r^2h$

Equating it to 4

$\displaystyle \pi r^2h=4$

Let's solve for h

$\displaystyle h=\frac{4}{\pi r^2}$

A cylinder with an open-top has only one circle as the shape of the lid and has a lateral area computed as a rectangle of height h and base equal to the length of a circle. Thus, the total area of the material to make the cylinder is

$\displaystyle A=\pi r^2+2\pi rh$

Replacing the formula of h

$\displaystyle A=\pi r^2+2\pi r \left (\frac{4}{\pi r^2}\right )$

Simplifying

$\displaystyle A=\pi r^2+\frac{8}{r}$

We have the function of the area in terms of one variable. Now we compute the first derivative and equal it to zero

$\displaystyle A'=2\pi r-\frac{8}{r^2}=0$

Rearranging

$\displaystyle 2\pi r=\frac{8}{r^2}$

Solving for r

$\displaystyle r^3=\frac{4}{\pi }$

$\displaystyle r=\sqrt[3]{\frac{4}{\pi }}\approx 1.084\ feet$

Computing h

$\displaystyle h=\frac{4}{\pi \ r^2}\approx 1.084\ feet$

We can see the height and the radius are of the same size. We check if the critical point is a maximum or a minimum by computing the second derivative

$\displaystyle A''=2\pi+\frac{16}{r^3}$

We can see it will be always positive regardless of the value of r (assumed positive too), so the critical point is a minimum.

The minimum area is

$\displaystyle A=\pi(1.084)^2+\frac{8}{1.084}$

$\boxed{ A=11.07\ ft^2}$

8 0

3 years ago

Which type of factoring is used to factor the following expression: 2x^2 + 7x- 30

svetlana [45]

Answer:

(2x - 5) • (x + 6)

7 0

3 years ago

A trip to another city is 180 miles. In miles per hour to the nearest tenth, how fast does one have to drive to average 60 mph o

irakobra [83]

Answer:

63.5

Step-by-step explanation:

If one didn't take a 10 minute break he could drive 60 mph totalling 180 minutes but since he did and 180 - 10 = 170. He/she has to drive 180 miles in 170 min. so we take so we divde 180/170 and multiply by 60. If you round it to the nearest tenth you get 63.5

7 0

3 years ago