Find the quotient below. Write the answer as a fraction in simplest form.
1 answer:
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Answer:
Yes , function is continuous in [0,2] and is differentiable (0,2) since polynomial function are continuous and differentiable
Step-by-step explanation:
We are given the Function
f(x) =
The two basic hypothesis of the mean valued theorem are
- The function should be continuous in [0,2]
- The function should be differentiable in (1,2)
upon checking the condition stated above on the given function
f(x) is continuous in the interval [0,2] as the functions is quadratic and we can conclude that from its graph
also the f(x) is differentiable in (0,2)
f'(x) = 6x - 2
Now the function satisfies both the conditions
so applying MVT
6x-2 = f(2) - f(0) / 2-0
6x-2 = 9 - 1 /2
6x-2 = 4
6x=6
x=1
so this is the tangent line for this given function.
Answer:
3.7feet
Step-by-step explanations
Using the sin rule
A/sin a = B/sin b
Let A = PQ = 8.5feet
B = QR = x feet
a = R = 90°
b = P = 26°
Substitute the values into the Sin rule
8.5/sin90 = x/sin26
8.5×sin 26 = x × sin 90
8.5×0.4383 = x× 1
3.7255 = x
Hence the length of QR to the nearest tenth 3.7feet
