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3 years ago

What are the answers to these

Mathematics

1 answer:

vladimir1956 [14]3 years ago

6 0

In the picture you can see the steps
X=32

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Question

AlekseyPX

Answer:

The population mean is 5 volts

Step-by-step explanation:

Output voltage is assumed to be normally distributed, with standard deviation 0.25 Volts

s=0.25

n = 8

$H_0:\mu = 5\\H_a:\mu \neq 5$

Sample mean = $\bar{x}=4.85$

Since n < 30 and population standard deviation is unknown

So, we will use t test

Formula : $t = \frac{x-\mu}{\frac{s}{\sqrt{n}}}$

$t = \frac{4.85-5}{\frac{0.25}{\sqrt{8}}}$

t=-1.69

Refer the t table for p value

Degree of freedom = n-1 = 8-1 = 7

So, $t_{(df,\alpha)}=t_{7,0.05}=2.365$

P value >α

So, We are failed to reject null hypothesis

Hence The population mean is 5 volts

7 0

3 years ago

What is the solution to the system of equations? HELP

notsponge [240]

I will solve your system by substitution.x=−2;y=23x+3Step: Solvex=−2for x:Step: Substitute−2forxiny=23x+3:y=23x+3y=23(−2)+3y=53(Simplify both sides of the equation)

Answer:x=−2 and y=5/3

so the answer is B (the second choice)
(Hope it helped ^_^)

4 0

3 years ago

Read 2 more answers

I need help with this question about similar triangles

Colt1911 [192]

Answer:

ST = 12 units

Step-by-step explanation:

Δ RAS and Δ TES are similar triangles, thus the ratios of corresponding sides are equal, that is, noting that SR = 21 - ST, thus

$\frac{ST}{SR}$ = $\frac{TE}{AR}$ substitute values

$\frac{ST}{21-ST}$ = $\frac{8}{6}$ ( cross- multiply )

6ST = 8(21 - ST)

6ST = 168 - 8ST ( add 8ST to both sides )

14ST = 168 ( divide both sides by 14 )

ST = 12

6 0

3 years ago

Solve the equation using the quadratic formula. Enter each solution in simplest form.

sergeinik [125]

For this case we have the following quadratic equation:

$x ^ 2-4x + 23 = 0$

The solutions will be given by:

$x = \frac {-b \pm \sqrt {b ^ 2-4 (a) (c)}} {2a}$

Where:

$a = 1\\b = -4\\c = 23$

Substituting the values we have:

$x = \frac {- (- 4) \pm \sqrt {(- 4) ^ 2-4 (1) (23)}} {2 (1)}\\x = \frac {4 \pm \sqrt {16-92}} {2}\\x = \frac {4 \pm \sqrt {-76}} {2}\\x = \frac {4 \pm \sqrt {76i ^ 2}} {2}\\x = \frac {4 \pmi \sqrt {76}} {2}\\x = \frac {4 \pmi \sqrt {2 ^ 2 * 19}} {2}\\x = \frac {4 \pm2i \sqrt {19}} {2}\\x = 2 \pm i\sqrt {19}$