Write the equation of a line that is parallel to y = 6x +1 and that passes through the point (-7,1).
1 answer:
Answer:
Step-by-step explanation:
We want the equation of a line that is parallel to which also passes through (-7, 1).
Since the new line is parallel, it must have the same slope as the original line.
The slope of the original line is 6.
Hence, the slope of our new line must also be 6.
We know that the slope is 6.
And it passes through the point (-7, 1).
So, we can use the point-slope form:
Where m is the slope and (x₁, y₁) is a point.
Substitute:
Simplify:
Distribute:
Add 1 to both sides. Hence, our equation is:
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Answer:
Step-by-step explanation:
GIVEN : In ΔPQR
S is the mid point of QP
U is the mid point of PR
T is the mid point of QR
Solution :
i) is true i.e
Refer the attached file
By mid segment theorem i.e. In a triangle, the line joining the midpoints of any two sides will be parallel to the third side and that same line joining the midpoints is also half of length of third side .
UT is the line joining the two mid points . So, by theorem given above UT is parallel to PQ and 1/2QP=UT.
So, (i) statement is true i.e.
