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agasfer [191]
3 years ago
6

A total of $8000 is invested: part at 8% and the remainder at 12%. How much is invested at each rate if the annual interest is $

650?
Mathematics
1 answer:
inna [77]3 years ago
4 0

Answer:

8% = $7750

12% = $250

Step-by-step explanation:

I P R. T.

8% X .08 .08X

12% 8000-X .12 .12(8000-X)

.08X + .12(8000-X) = 650

.08X + 960 - .12X = 650

<u> </u><u> </u><u> -960 </u><u> </u><u> </u><u> -960</u>

.08x - .12x = -310

<u>-.04x</u><u> </u><u>=</u><u> </u><u>-310</u>

-.04x -.04x

X = 7750

Verify:

X = 7750

8000 - X = 250

250 + 7750 = 8000

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