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3 years ago

A middle school needs buses to

Mathematics

2 answers:

Tresset [83]3 years ago

7 0

Answer:

13 buses ml hope that helps

cricket20 [7]3 years ago

4 0

Answer:

13 buses

Step-by-step explanation:

There are 579 students and each bus carries 48 students so:

579 ÷ 48 = 12.1

Now you could say that only 12 buses are needed but there would be an extra student remaining so you need 13 buses.

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PLEASE HELP <br><br> THERE ARE MANY QUESTIONS LIKE THIS ON MY PAGE SO U CAN JUST KEEP GETTING POINTS

Nastasia [14]

Answer: 1

Step-by-step explanation:

first, i multiplied it all out.

1.5^2/1.5^2

then, i simply divided it all.

8 0

3 years ago

Find the product of 2/5 with the quotient of 7/3 and 4/5

marissa [1.9K]

Answer:

7/6

Step-by-step explanation:

7/3÷4/5

7/3×5/4

35/12

Now the multiplication

2/5×35/12

70/60

7/6

6 0

2 years ago

Which graph represents (x - 1)2/9 (y-3)2/1

Marat540 [252]

We can only see one graph here

7 0

3 years ago

Read 2 more answers

All 231 students in math club went on a field trip some rode in vans that held 7 people and some rode on buses that held 25 peop

MariettaO [177]

Answer:

8 vans

7 buses

Step-by-step explanation:

Let there be "b" buses

and "v" vans

Since 7 people is the capacity of vans, the total capacity is

Also, since 25 people is the capacity of 1 bus, the total capacity is

25b

In total 231 people, so we can write our first equation as:

7v + 25b = 231

Now, we know there are 15 vehicles (bus + vans) in total, so we can write our 2nd equation as:

v + b = 15

Now, we solve for v and b. Let's solve the 2nd equation for v and substitute that into 1st and solve for b first:

v + b = 15

v = 15 - b

Now,

$7v + 25b = 231\\7(15-b) + 25b = 231\\105-7b+25b=231\\18b=126\\b=7$

Hence, there are 7 buses

Since 15 vehicles in total, the number of vans is:

15 - 7 = 8 vans

So,

8 vans

7 buses

8 0

4 years ago

1.This circle is centered at the origin and contains the points two units away. Write the equation for this circle.

denis-greek [22]

Answer:

1. The location of the center of the given circle = The origin (0, 0)

The given points on the circumference of the circle = (1, √3), and (0, -2)

The general form of the equation of a circle, is presented as follows

(x - h)² + (y - k)² = r²

Where;

(h, k) = The coordinates of the center of the circle

r = The radius of the circle

∴ (h, k) = (0, 0)

The radius of the given equation is the distance from the center (0, 0) to either the point (0, -2) or (1, √3)

The distance from the center (0, 0) to the point (0, -2), which are points on the same ordinate, r = y₂ - y₁

∴ r = 0 - (-2) = 2

r = 2

The equation of the circle is therefore;

(x - 0)² + (y - 0)² = 2²

∴ x² + y² = 2²

2. When x = 1, and y = √3, we have;

(1 - 0)² + (√3 - 0)² = 1 + 3 = 4 = 2²

When x = 0, and y = -2, we have;

(0 - 0)² + ((-2) - 0)² = (-2)² = 4 = 2²

Therefore, the points shown on the circle (1, √3), and (0, -2) satisfy the equation of the circle, x² + y² = 2² and are solutions to the equation of the circle

Step-by-step explanation:

3 0

3 years ago