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2 years ago

A middle school needs buses to

Mathematics

2 answers:

Tresset [83]2 years ago

7 0

Answer:

13 buses ml hope that helps

cricket20 [7]2 years ago

4 0

Answer:

13 buses

Step-by-step explanation:

There are 579 students and each bus carries 48 students so:

579 ÷ 48 = 12.1

Now you could say that only 12 buses are needed but there would be an extra student remaining so you need 13 buses.

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A family went to a baseball game. The cost to park cars was $5 and the cost per ticket was $21. Write a linear function in the f

Sophie [7]

Answer:

The total cost $y$ in dollars of going to the baseball game for $x$ people of a family can be given as:

$y=21x+5$

Step-by-step explanation:

Given:

At a baseball game:

Cost of car parking = $5

Cost per ticket = $21

To write an equation in the form of $y=mx+b$ representing the total cost of going to the baseball game.

Solution:

The total number of people in the family is = $x$

Using unitary method to find the cost of tickets for $x$ persons.

If 1 ticket costs = $21

<em>Then, $x$ tickets will cost in dollars</em><em> = </em> $21x$

Fixed rate for car parking = $5

Thus, the total cost $y$ in dollars of going to the baseball game for $x$ people of a family can be given as:

$y=21x+5$

5 0

3 years ago

Outline the process for inscribing a square in a circle. Perform the construction in GeoGebra, and take a screenshot of the cons

Amiraneli [1.4K]

Answer:

Mark a circle with point A in the center

Make two points across from each othe at the top and bottom of the circle. Mark them as B, C, D, and E

Connect the point B, C, D, and E using line segments

4 0

3 years ago

A company claims that the mean weight per apple they ship is 120 grams with a standard deviation of 12 grams. Data generated fro

Veronika [31]

Answer:

There is no sufficient evidence to reject the company's claim at the significance level of 0.05

Step-by-step explanation:

Let $\mu$ be the true mean weight per apple the company ship. We want to test the next hypothesis

$H_{0}:\mu=120$ vs $H_{1}:\mu\neq 120$ (two-tailed test).

Because we have a large sample of size n = 49 apples randomly selected from a shipment, the test statistic is given by

$Z=\frac{\bar{X}-120}{\sigma/\sqrt{n}}$ which is normally distributed. The observed value is

$z_{0}=\frac{122.5-120}{12/\sqrt{49}}=1.4583$ . The rejection region for $\alpha = 0.05$ is given by RR = {z| z < -1.96 or z > 1.96} where the area below -1.96 and under the standard normal density is 0.025; and the area above 1.96 and under the standard normal density is 0.025 as well. Because the observed value 1.4583 does not fall inside the rejection region RR, we fail to reject the null hypothesis.