<span>Answer:
Its too long to write here, so I will just state what I did.
I let P=(2ap,ap^2) and Q=(2aq,aq^2)
But x-coordinates of P and Q differ by (2a)
So P=(2ap,ap^2) BUT Q=(2ap - 2a, aq^2)
So Q=(2a(p-1), aq^2)
which means, 2aq = 2a(p-1)
therefore, q=p-1
then I subbed that value of q in aq^2
so Q=(2a(p-1), a(p-1)^2)
and P=(2ap,ap^2)
Using these two values, I found the midpoint which was:
M=( a(2p-1), [a(2p^2 - 2p + 1)]/2 )
then x = a(2p-1)
rearranging to make p the subject
p= (x+a)/2a</span>
Answer:
x-2
Step-by-step explanation:
x3−3x2+3x−2/x2−x+1
=
x3−3x2+3x−2/x2−x+1
=
(x−2)(x2−x+1)/x2−x+1
=x−2
Answer:
39+10=49
Step-by-step explanation:
I hope this helps you.
Answer:
4.6 hours
Step-by-step explanation:
we first need to calculate the total distance he covered and total time taken whole for the journey.
Distance= speed X time
time = Distance/speed
let the total distance be X. he covers 2/5 if the journey first.
2/5 = 0.4
Time = 0.4x/45 hours
the remaining journey is 3/5x
he covers 1/3 X 3/5= 0.2x
time taken = 0.2/90 X hours
the remaining distance = 100× 1.2 = 120km
we add 0.4x + 0.2x to get the fraction he had covered
0.6x.
the remaining distance was X - 0.6x = 0.4 X
thus 120 km represents 0.4x of the journey
we calculate now the value of X
0.4x = 120
X = 300km
Total time taken = 0.4x/45 + 0.2/90 + 1.2 hours
replace X to get time
2.7 hours + 0.7 hours + 1.2 hours
= 4.6 hours
