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notka56 [123]
3 years ago
15

Ricardo has a sandbox in the shape of a cylinder 5 feet in diameter. He plans to fill the sandbox with sand to a depth of 0.5 fe

et. The sand has a density of 90 pounds per cubic foot.
How many 50-pound bags of sand will Ricardo need to buy in order to fill the sandbox?
Mathematics
1 answer:
s344n2d4d5 [400]3 years ago
6 0

Answer:

36

Step-by-step explanation:

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Select all the correct answers. Which of these relations are functions?
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The answer is A C D your answer
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At the hardware store, you purchase a box of nails originally worth $14.99. You have a coupon for 20% off the nails. Sales tax i
arlik [135]

The total price for the nails is $ 12.71.

Since at the hardware store, you purchase a box of nails originally worth $ 14.99, and you have a coupon for 20% off the nails, and sales tax is 6%, to determine what is the total cost for the nails, the following calculation must be made:

  • Original price - discount + tax = Total price
  • (14.99 x 0.8) x 1.06 = X
  • 11.992 x 1.06 = X
  • 12.71 = X

Therefore, the total price for the nails is $ 12.71.

Learn more in brainly.com/question/20162367

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3 years ago
Anna built a prism (Prism A) out of a cube of wood. The side length of the cube measured 18 inches in length. Anna built another
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Answer:

The volume of the prism B will double

Step-by-step explanation:

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3 years ago
SOLVE USING THE QUADRATIC FORMULA <br><br> 1) y=3x^2-x-6<br><br> 2) y=-5x^2+7x+3
kondor19780726 [428]

1) x=\frac{1+\sqrt{73}}{6}\,\,and\,\,x=\frac{1-\sqrt{73}}{6}

2) x=\frac{-7+\sqrt{109}}{-10}\,\,and\,\,x=\frac{-7-\sqrt{109}}{-10}

Step-by-step explanation:

Solving the equations using quadratic formula.

1) y=3x^2-x-6

The quadratic formula is:

x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}

where a =3, b = -1 and c= -6

Putting values:

x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}\\x=\frac{-(-1)\pm\sqrt{(-1)^2-4(3)(-6)}}{2(3)}\\x=\frac{1\pm\sqrt{1+72}}{6}\\x=\frac{1\pm\sqrt{73}}{6}\\so, x=\frac{1+\sqrt{73}}{6}\,\,and\,\,x=\frac{1-\sqrt{73}}{6}

2) y=-5x^2+7x+3

The quadratic formula is:

x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}

where a =-5, b = 7 and c= 3

Putting values:

x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}\\x=\frac{-(7)\pm\sqrt{(7)^2-4(-5)(3)}}{2(-5)}\\x=\frac{-7\pm\sqrt{49+60}}{-10}\\x=\frac{-7\pm\sqrt{109}}{-10}\\So, x=\frac{-7+\sqrt{109}}{-10}\,\,and\,\,x=\frac{-7-\sqrt{109}}{-10}

Keywords: Solving Using Quadratic Formula

Learn more about Solving Using Quadratic Formula at:

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#learnwithBrainly

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