Check the picture below, now the distance from 2,0 to 4,0 there's no need to do much calculation since that's just 2 units, as you see there.
![~\hfill \stackrel{\textit{\large distance between 2 points}}{d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2}}~\hfill~ \\\\[-0.35em] ~\dotfill\\\\ (\stackrel{x_1}{2}~,~\stackrel{y_1}{0})\qquad (\stackrel{x_2}{1}~,~\stackrel{y_2}{4}) ~\hfill d1=\sqrt{[ 1- 2]^2 + [ 4- 0]^2} \\\\\\ d1=\sqrt{(-1)^2+4^2}\implies \boxed{d1=\sqrt{17}} \\\\[-0.35em] ~\dotfill](https://tex.z-dn.net/?f=~%5Chfill%20%5Cstackrel%7B%5Ctextit%7B%5Clarge%20distance%20between%202%20points%7D%7D%7Bd%20%3D%20%5Csqrt%7B%28%20x_2-%20x_1%29%5E2%20%2B%20%28%20y_2-%20y_1%29%5E2%7D%7D~%5Chfill~%20%5C%5C%5C%5C%5B-0.35em%5D%20~%5Cdotfill%5C%5C%5C%5C%20%28%5Cstackrel%7Bx_1%7D%7B2%7D~%2C~%5Cstackrel%7By_1%7D%7B0%7D%29%5Cqquad%20%28%5Cstackrel%7Bx_2%7D%7B1%7D~%2C~%5Cstackrel%7By_2%7D%7B4%7D%29%20~%5Chfill%20d1%3D%5Csqrt%7B%5B%201-%202%5D%5E2%20%2B%20%5B%204-%200%5D%5E2%7D%20%5C%5C%5C%5C%5C%5C%20d1%3D%5Csqrt%7B%28-1%29%5E2%2B4%5E2%7D%5Cimplies%20%5Cboxed%7Bd1%3D%5Csqrt%7B17%7D%7D%20%5C%5C%5C%5C%5B-0.35em%5D%20~%5Cdotfill)
![(\stackrel{x_1}{1}~,~\stackrel{y_1}{4})\qquad (\stackrel{x_2}{-1}~,~\stackrel{y_2}{-2}) ~\hfill d2=\sqrt{[ -1- 1]^2 + [ -2- 4]^2} \\\\\\ d2=\sqrt{(-2)^2+(-6)^2}\implies \boxed{d2=\sqrt{40}} \\\\[-0.35em] ~\dotfill\\\\ (\stackrel{x_1}{-1}~,~\stackrel{y_1}{-2})\qquad (\stackrel{x_2}{4}~,~\stackrel{y_2}{0}) ~\hfill d3=\sqrt{[ 4- (-1)]^2 + [ 0- (-2)]^2} \\\\\\ d3=\sqrt{(4+1)^2+(0+2)^2}\implies \boxed{d3=\sqrt{29}}](https://tex.z-dn.net/?f=%28%5Cstackrel%7Bx_1%7D%7B1%7D~%2C~%5Cstackrel%7By_1%7D%7B4%7D%29%5Cqquad%20%28%5Cstackrel%7Bx_2%7D%7B-1%7D~%2C~%5Cstackrel%7By_2%7D%7B-2%7D%29%20~%5Chfill%20d2%3D%5Csqrt%7B%5B%20-1-%201%5D%5E2%20%2B%20%5B%20-2-%204%5D%5E2%7D%20%5C%5C%5C%5C%5C%5C%20d2%3D%5Csqrt%7B%28-2%29%5E2%2B%28-6%29%5E2%7D%5Cimplies%20%5Cboxed%7Bd2%3D%5Csqrt%7B40%7D%7D%20%5C%5C%5C%5C%5B-0.35em%5D%20~%5Cdotfill%5C%5C%5C%5C%20%28%5Cstackrel%7Bx_1%7D%7B-1%7D~%2C~%5Cstackrel%7By_1%7D%7B-2%7D%29%5Cqquad%20%28%5Cstackrel%7Bx_2%7D%7B4%7D~%2C~%5Cstackrel%7By_2%7D%7B0%7D%29%20~%5Chfill%20d3%3D%5Csqrt%7B%5B%204-%20%28-1%29%5D%5E2%20%2B%20%5B%200-%20%28-2%29%5D%5E2%7D%20%5C%5C%5C%5C%5C%5C%20d3%3D%5Csqrt%7B%284%2B1%29%5E2%2B%280%2B2%29%5E2%7D%5Cimplies%20%5Cboxed%7Bd3%3D%5Csqrt%7B29%7D%7D)
Answer:
B) No, supplementary angles are either of two angles whose sum is 180 degrees.
C) Yes, the triangles are congruent because the triangles have exactly the same size and shape
Step-by-step explanation:
B) From the image below an 180 degree angle would be obtuse in which neither angle appears to be so they are not supplementary.
C) They are congruent because they are taking angles of the same angles as one another just on different sides of the shape.
They are all wrong lol
(x-8)^2+(y+8)^2=121
Answer:
16.4 m to the nearest tenth.
Step-by-step explanation:
After the first bounce it rises to a height of 50*0.8 = 40 m.
After the next bounce it rises to 50*(0.8)^2 = 32 m
So after the 5th bounce it rises to 50(0.8)^5 = 16.4 m. (answer).
