Let’s call the speed of the slower car S, then the speed of the other is S+10mph.
At 5pm they have been travelling for 3 hours. The slower car travels a distance 3S and the faster one 3(S+10).
But the two distances must add up to 240 miles so 3S+3(S+10)=240, 3S+3S+30=240, 6S=210, S=35 mph. The faster car’s speed is 45mph. We can see that 3S is the same distance as 3x, so x=S=35 mph, and the distance the faster car travels is 3×45=135 miles.
0.6cm or 6mm if you take 5*12% you can get the answer pretty easy :)
I would appriciate Brainliest!
Answer:
Length: 7
Width: 4
Step-by-step explanation:
We can create a system of equations for this problem, where
is the width and
is the length.
The perimeter of a rectangle is twice its length added to twice its width.
![2l+2w=22](https://tex.z-dn.net/?f=2l%2B2w%3D22)
The length is 3 more than the width:
![l = w+3](https://tex.z-dn.net/?f=l%20%3D%20w%2B3)
We can now substitute in
as
in the equation
.
![2(w+3) + 2w = 22](https://tex.z-dn.net/?f=2%28w%2B3%29%20%2B%202w%20%3D%2022)
Distribute the first terms:
![2w+6+2w=22](https://tex.z-dn.net/?f=2w%2B6%2B2w%3D22)
Combine like terms:
![4w+6=22](https://tex.z-dn.net/?f=4w%2B6%3D22)
Subtract 6 from both sides:
![4w=16](https://tex.z-dn.net/?f=4w%3D16)
Divide both sides by 4:
![w = 4](https://tex.z-dn.net/?f=w%20%3D%204)
Now we know that w = 4. We can now substitute this inside an equation to find
.
![l = w+3\\\\l = 4+3\\\\l=7](https://tex.z-dn.net/?f=l%20%3D%20w%2B3%5C%5C%5C%5Cl%20%3D%204%2B3%5C%5C%5C%5Cl%3D7)
Hope this helped!
...........................
Answer:its 10 :)
Step-by-step explanation: