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4 years ago

What is the domain of F(x)=1/x?

Mathematics

1 answer:

sesenic [268]4 years ago

6 0

Answer:

Step-by-step explanation:

Given f(x) = $\frac{1}{x}$

The denominator of f(x) cannot be zero as this would make f(x) undefined. Equating the denominator to zero and solving gives the value that x cannot be.

denominator : x = 0 ← excluded value

domain : x ∈ R, x≠ 0

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Suppose 2' is a normally distributed random variable with ft = 10.3 and 0 = 3.8. For the following probability,draw an appropria

TiliK225 [7]

GIVEN

The following values are given:

$\begin{gathered} \mu=10.3 \\ \sigma=3.8 \end{gathered}$

SOLUTION

The z-score for the x values 9 and 14 can be calculated using the formula:

$z=\frac{x-\mu}{\sigma}$

For x = 9:

$\begin{gathered} z=\frac{9-10.3}{3.8} \\ z=-0.34 \end{gathered}$

For x = 14:

$\begin{gathered} z=\frac{14-10.3}{3.8} \\ z=0.97 \end{gathered}$

The probability can be calculated as follows:

$P(9\le x\le14)=Pr(-0.34The region that represents the solution is shown below:Therefore, the probability is given to be:[tex]P(9\le x\le14)=0.4671$

The probability is 0.4671.

8 0

1 year ago

Isn't A B and D correct?

faust18 [17]

Answer:

I think the answer is B.

Step-by-step explanation:

I'm just going by how it looks but I am pretty sure that n is -0.5 and m is 2.5. Therefore, if you add -0.5 + 2.5 it equals 2.0.

8 0

3 years ago

Which parabola has the graph shown? I think the answer is C. however, I'm not 100% sure.

NemiM [27]

$x=m(y-k)^2+h\\\\(h,\ k)-the\ vertex$

We have the vertex (-4, -1), therefore we have:

$x=(y-(-1))^2-4\ \ \ |+4\\\\(x+4)=(y+1)^2$

7 0

3 years ago

Solve for f. 8 = 2f + 2

tiny-mole [99]

Answer:

f = 3

Step-by-step explanation:

8 = 2f + 2

-2 -2

6 = 2f

/2 /2

3 = f

5 0

3 years ago

If 5=3+2,then 3+2=5. What is the truth value

olga nikolaevna [1]

Answer:

true

Step-by-step explanation:

6 0

3 years ago