Acute triangle; m<CDB = 180 - 130 = 50 and m<2 = 180 - 70 - 50 = 60.
<em>reme</em><em>mber</em><em> </em><em>that</em><em> </em><em>all</em><em> </em><em>angles </em><em>in</em><em> </em><em>a</em><em> </em><em>tria</em><em>ngle</em><em> </em><em>add</em><em> </em><em>up</em><em> </em><em>to</em><em> </em><em>1</em><em>8</em><em>0</em><em>°</em><em>.</em>
<em>And </em><em>angles </em><em>on</em><em> </em><em>a</em><em> </em><em>straight</em><em> </em><em>line</em><em> </em><em>add</em><em> </em><em>up</em><em> </em><em>to</em><em> </em><em>1</em><em>8</em><em>0</em><em>°</em><em>.</em>
Answer:
Substituting the {3,-11/3} the equation is satisfied for the both values individually. Also it can be satisfied by solving the equation 3x2+2x-33=0 and giving the roots as x=3 and x=-11/3
Step-by-step explanation:
I think
41.8 × 1.9 = <span>79.42
So he is correct!
A. Yes, Vincent's answer is reasonable.</span>
Answer:
2. y = 7/2 x -2
3. y = 3/4x-1
Step-by-step explanation:
points (0,-2) (4,12)
slope = (y2-y1)/(x2-x1)
slope = (12--2)/(4-0)
= (12+2)/4
= 14/4 = 7/2
the slope is 7/2 and the y intercept is -2
y = mx+b
y = 7/2 x -2
points (0,-1) (4,2)
slope = (y2-y1)/(x2-x1)
slope = (2--1)/(4-0)
= (2+1)/4
= 3/4
the slope is 3/4 and the y intercept is -1
y = mx+b
y = 3/4x-1