Answer:
Assume:
(angle) RSB and angle (LSA) = D
and (line) ASR and (line) LSB is striaght then
(9x +27) + D = 180
(6x + 66) + D = 180
9x + D = 153
6x + D = 114
substitute
6x + D = 114
D = 114 - 6 x
9x + (114 - 6x) =153
3x = 39
x = 13
D = 114 - 6(13)
D=36
Step-by-step explanation:
Answer:
![\boxed {x = -15}](https://tex.z-dn.net/?f=%5Cboxed%20%7Bx%20%3D%20-15%7D)
Step-by-step explanation:
Solve for the value of
:
![x + 7 = -8](https://tex.z-dn.net/?f=x%20%20%2B%207%20%3D%20-8)
-Subtract both sides by
:
![x + 7 - 7 = -8 - 7](https://tex.z-dn.net/?f=x%20%2B%207%20-%207%20%3D%20-8%20-%207)
So, the value of
is
.
Answer:
Step-by-step explanation:
We would apply the formula for determining compound interest which is expressed as
A = P(1+r/n)^nt
Where
A = total amount in the account at the end of t years
r represents the interest rate.
n represents the periodic interval at which it was compounded.
P represents the principal or initial amount deposited
From the information given,
P = $470
r = 6% = 6/100 = 0.06
n = 1 because it was compounded once in a year.
Therefore, the equation used to determine the value of his bond after t years is
A = 470(1 + 0.06/1)^1 × t
A = 470(1.06)^t
Answer:
to what
Step-by-step explanation:
Answer:
Step-by-step explanation: