This is a true statement.
Consider two events A and B. We say they are complementary if P(A)+P(B) = 1
This means that either event A or event B must happen, since the "1" represents 100% probability. Having a probability of 100% means absolute certainty.
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Example:
A = the event it rains
B = the event it does not rain
P(A) = 0.30 = 30% chance of rain
P(B) = 0.70 = 70% chance it does not rain
P(A)+P(B) = 0.30+0.70 = 1
So this shows the two events are complementary.
Answer:
23
Step-by-step explanation:
Given Shane hits 5 HRs out of 100 At-bats,

Given:
The function is

To find:
The inverse of the given function.
Solution:
We have,

Substitute m(x)=y.

Interchange x and y.

Add square of half of coefficient of y , i.e.,
on both sides,


![[\because (a-b)^2=a^2-2ab+b^2]](https://tex.z-dn.net/?f=%5B%5Cbecause%20%28a-b%29%5E2%3Da%5E2-2ab%2Bb%5E2%5D)
Taking square root on both sides.

Add
on both sides.

Substitute
.

We know that, negative term inside the root is not real number. So,


Therefore, the restricted domain is
and the inverse function is
.
Hence, option D is correct.
Note: In all the options square of
is missing in restricted domain.
You said that P = I · R · T
Divide each side by I · R : P / (I·R) = T
Answer:
C. 4
Step-by-step explanation:
Since this one is already graphed and we can see it clearely we can just count, but you can also do change in y over change in x (aka "rise over run") to find the slope.
So, we count and find it is four up and one over. 4/1 = 4 = c
Hope this helps, have a nice day! :)