Question

Suppose that the function h is defined, for all real numbers, as follows.

Answer 1

Answer:

gsgdjdjchdvvdbdjzjsjsushsvvsvsvs I don't know

Answer 2

Answer:

see explanation

Step-by-step explanation:

h(- 3) with x = - 3, that is x ≠ 1 , then

h(- 3) = - $\frac{1}{2}$ (- 3) + 2 = $\frac{3}{2}$ + 2 = $\frac{7}{2}$

h(1) with x = 1 , then

h(1) = 1

h(3) with x = 3, that is x ≠ 1 , then

h(3) = - $\frac{1}{2}$ (3) + 2 = - $\frac{3}{2}$ + 2 = $\frac{1}{2}$