Really need help with this
1 answer:
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Since the angles in triangle ACM indicate that it is a 30-60-90 triangle, we know that the other two sides of triangle ACM are 20 and 10 (30-60-90 triangles have a very specific side coefficient). This means that the sides of this triangle have side lengths 40, 10, and 
. Adding these together you get 50+. Hope this helps!
The vertical distance can be found by subtracting parabola from the given line.
Given line equation is y= x+20
Equation of parabola is y= x^2
Subtract parabola from line equation
so y =
y =
Now we take derivative to find out the maximum that is the vertex
y' = -2x + 1
Now we set derivative =0 and solve for x
0 = -2x+1
2x = 1
Now we plug in x values in
Take common denominator
So our maximum vertical distance is at