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Bond [772]
3 years ago
15

How is a newborn baby's skull different from an adult's skull?

Medicine
2 answers:
MariettaO [177]3 years ago
6 0

Answer:

Its smaller

Explanation:

Im sorry this is totally not helpful ;)

maw [93]3 years ago
3 0
A baby’s skull is probably still not fully developed as an adults and its smaller than adults but they can Amos have big skills to
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If your eye was punctured by a large needle, what gel-like material would come out?
Svetradugi [14.3K]

Explanation:

i believe it is a or b because i think it just makes sense

8 0
3 years ago
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Blood coagulation is initiated by either the intrinsic or extrinsic pathway. The final step inboth pathways would be:
Murrr4er [49]

Answer:The final step in both pathways would be the activation of factor X, leading to conversion of prothrombin II to thrombin IIa. Option C.

Explanation: blood coagulation is the processes that leads to blood clot formation. The blood clot formed is made up of fibrin and platelets, which forms hemostatic plug over a wound site. The blood coagulation is made up of two partways that led to the formation of clot. The intrinsic pathway also called contact activation pathway and the extrinsic pathway which is also known as the tissue factor pathway. The both pathways are connected by a common pathway whereby factor X is activated leading to leading to conversion of prothrombin II to thrombin IIa. Thrombin then converts fibrinogen to fibrin( blood clot). I hope this helps. Thanks.

4 0
3 years ago
Which can cause miscarriage, premature births, and blindness in inborn?
adoni [48]

Answer:

toxoplasmosis

Explanation:

6 0
3 years ago
Which BEST describes the association between taking benzisoxazole for schizophrenia and amoxapine for depression?
marta [7]

Answer:

c. Benzisoxazole increases serotonin levels, while amoxapine decreases serotoonin levels

6 0
2 years ago
All of the following expressions are equal except _____. 2 ^ -3 8 1/8 2^1/2^4 math
Brilliant_brown [7]

Explanation:

Option 1 is 2^{-3}

Property is : x^{-y}=\dfrac{1}{x^y}

So, 2^{-3}=\dfrac{1}{2^3}=\dfrac{1}{8}

Option 2 is 8\dfrac{1}{8}

We can write it as : 8\dfrac{1}{8}=\dfrac{8(8)+1}{8}=\dfrac{65}{8}

Option 3 is \dfrac{2^1}{2^4}

Property is : \dfrac{x^a}{x^b}=x^{a-b}

So,

\dfrac{2^1}{2^4}=\dfrac{1}{2^3}\\\\=2^{-3}\\\\=\dfrac{1}{8}

It is clear that option a and c are same. But option b is different.

8 0
3 years ago
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