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3 years ago

Please help I don’t understand

Mathematics

1 answer:

Firlakuza [10]3 years ago

6 0

Answer:

1/2

Step-by-step explanation:

y = mx + b

the "m" is the slope

and the b is the y-intercept

as you can see from the equation y = 1/2x + 3

the 1/2 substituted the m which is the slope

so the slope of the line is 1.2

Hope this helped!

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3 years ago

Drawing a red marble from a bag of six red and 4 blue replacing it and then drawing a blue marble

Ksivusya [100]

Answer:

The probability of picking a red marble and a blue marble = 6/25

Step-by-step explanation:

Here, the question is INCOMPLETE.

What is the probability of this independent event. Drawing a red marble from a bag of 6 red and 4 blue marbles, replacing it, and then drawing a blue marble.

Here, total number of red marble in bag = 6

total number of blue marble in bag = 4

So, total marbles in the bag = 6 + 4 = 10 marbles

Now,if E : Any given event, then

$\textrm{P (Event E)} = \frac{\textrm{Total number of favorable outcomes}}{\textrm{Total Outcomes}}$

So, here $\textrm{P (Picking a Red marble)} = \frac{\textrm{Total number of red marble}}{\textrm{Total marble}} = \frac{6}{10} = \frac{3}{5}$

⇒ P(a Red ball) = 3/5 ...... (1)

Now, if the picked marble is REPLACED, then total marbles in the bag = 10

So, here $\textrm{P (a Blue marble)} = \frac{\textrm{Total number of blue marble}}{\textrm{Total marble}} = \frac{4}{10} = \frac{2}{5}$

⇒ P(a Blue marble) = 2/5 ...... (2)

So, the probability of picking a red marble and a blue marble AFTER REPLACING

=P(a Red marble) x P(a Blue marble) = 3/5 x 2/5 = 6 /25

Hence, the probability of picking a red marble and a blue marble = 6/25

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