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3 years ago

GEOMETRY HELLP :)))))))))))))))))))))))))))))))))))))))))))))))

Mathematics

1 answer:

Ulleksa [173]3 years ago

7 0

Answer:

Step-by-step explanation:

angle S+angle T+angle+angle R=180 degree(being sum of interior angle of a triangle)

4x^2-6x+40+18x+3+2x^2-7=180

6x^2+12x+36=180

6(x^2+2x+6)=180

x^2+2x+6=180/6

x^2+2x+6=30

x^2+2x=24

x(x+2)=24

x+2=24/x

x=24/x-2

x=24-2x/x

substitute the value of x^2 in angle R

2x^2-7

2(24-2x/x)^2-7(here x and x gets cancel)

2(24-2)^2-7

2*22^2-7

2*484-7

968-7

961

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PLEASE HELP ANSWER THESE QUESTIONS!

Sliva [168]

Answer:

Step-by-step explanation:

a² - b² = (a+ b)(a - b)

1) (2n-4/2n) ÷ (n^2-4/n)

$=\frac{2n-4}{2n}*\frac{n}{n^{2}-4}\\\\=\frac{2n-2*2}{2n}*\frac{n}{n^{2}-2^{2}}\\\\=\frac{2*(n-2)}{2n}*\frac{n}{(n+2)*(n-2)}\\\\=\frac{1}{n+2}$

2) [y^2-36/y^2-49] ÷[ y+6/y-7]

$=\frac{y^{2}-36}{y^{2}-49}*\frac{y-7}{y+6}\\\\=\frac{y^{2}-6^{2}}{y^{2}-7^{2}}*\frac{y-7}{y+6}\\\\=\frac{(y+6)*(y-6)}{(y+7)*(y-7)}*\frac{y-7}{y+6}\\\\=\frac{y-6}{y+7}\\$

3) [m^2-1/ m^2-m] ÷ [m^2-7m-8/3m ]

$=\frac{m^{2}-1}{m^{2}-m}*\frac{3m}{m^{2}-7m-8}\\\\=\frac{(m+1)*(m-1)}{m*(m-1)}*\frac{3m}{(m-8)*(m+1)}\\\\=\frac{3}{m-8}$

Hint : m² - 7m - 8

sum = -7

Product = -8

Factor = (-8), 1

m² - 7m - 8 =m² - 8m + m - 8

= m*(m - 8) + (m-8)

= (m - 8)(m +1)

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3 years ago

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General solution for cos(5x)-cos(2x)=0

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