All categories

3 years ago

25 POINTS NO CAP PLEASE HELP ME NEED RIGHT ANSWER

Mathematics

2 answers:

Anuta_ua [19.1K]3 years ago

5 0

Answer:

2/1/3 x

Step-by-step explanation:

lys-0071 [83]3 years ago

3 0

2/-1x-3 is the answer!!

You might be interested in

Helpppppppppppppppppppp

a_sh-v [17]

In order going down:
5 3/5
6 5/6
4 2/3
10 1/3
11 2/3

3 0

3 years ago

Given collinear points E, F and G such that point F is the midpoint of segment EG. Find the new length of EG given that EF =5x+9

Veseljchak [2.6K]

Answer:

The length of EG is 58 units

Step-by-step explanation:

The midpoint of a segment divides it into two equal part

Let us use this rule to solve our question

∵ E, F, and G are collinear points

∵ Point F is the midpoint of segment EG

→ That means F divides EG into 2 equal segments EF and FG

∴ EF = FG

∵ EF = 5x + 9

∵ FG = 3x + 17

→ Equate them

∴ 5x + 9 = 3x + 17

→ Subtract 3x from both sides

∵ 5x - 3x + 9 = 3x - 3x + 17

∴ 2x + 9 = 17

→ Subtract 9 from both sides

∴ 2x + 9 - 9 = 17 - 9

∴ 2x = 8

→ Divide both sides by 2 to find x

∵ $\frac{2x}{2}=\frac{8}{2}$

∴ x = 4

→ Substitute x by 4 in EF and FG to find their lengths

∵ EF = 5(4) + 9 = 20 + 9 = 29

∵ FG = 3(4) + 17 = 12 = 17 = 29

∵ EG = EF + FG

∴ EG = 29 + 29 = 58

∴ The length of EG is 58 units

6 0

3 years ago

What’s a line equation passing through (14,-8) and (24,-3)

Nataly_w [17]

$\bf (\stackrel{x_1}{14}~,~\stackrel{y_1}{-8})\qquad (\stackrel{x_2}{24}~,~\stackrel{y_2}{-3}) \\\\\\ \stackrel{slope}{m}\implies \cfrac{\stackrel{rise} {\stackrel{y_2}{-3}-\stackrel{y1}{(-8)}}}{\underset{run} {\underset{x_2}{24}-\underset{x_1}{14}}}\implies \cfrac{-3+8}{10}\implies \cfrac{5}{10}\implies \cfrac{1}{2}$

$\bf \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{(-8)}=\stackrel{m}{\cfrac{1}{2}}(x-\stackrel{x_1}{14}) \\\\\\ y+8=\cfrac{1}{2}x-7\implies y=\cfrac{1}{2}x-15$

4 0

3 years ago

Can someone please help me with # 2 #13 thanks show work how it's done, please

zavuch27 [327]

Problem 13

10p+10q factors to 10(p+q). If we apply the distributive property, we can distribute the 10 to each term inside (p and q) to get

10(p+q) = (10 times p)+(10 times q) = 10*p + 10*q = 10p+10q

so we get the original expression again. Here 10 is the GCF of the two terms.

--------------------------------------------------------------

Plug p = 1 and q = 2 into the factored form

10*(p+q) = 10*(1+2) = 10*(3) = 30

As a check, let's plug those p,q values into the original expression

10*p+10*q = 10*1+10*2 = 10+20 = 30

We get the same output of 30

6 0

3 years ago

In the diagram, if KL=10, and MK=2, and JM=6 determine the value of MN. Show your work or explain how you arrived at your answer

kodGreya [7K]

Answer:

Step-by-step explanation:

JM is 6 riiite

and JMN should be an equilateral triangle so

4 0

3 years ago