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miskamm [114]
2 years ago
5

12x2 + 3x + 6 and -7x2 - 4x - 2

Mathematics
1 answer:
Semenov [28]2 years ago
8 0

Answer:

Step-by-step explanation:12x2 + 3x + 6 + (-7)x2 - 4x - 2 = 0

12•x•2 + 3•x + 6 + (-7)•x•2 - 4•x - 2 = 0

9x = -4

x = -4/

9

≈ -0.444444

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HELP 100 POINTS The population of a city is modeled with the function P=250,000e^0.013t​, where t is the number of years since 2
erma4kov [3.2K]
Pretty difficult problem, but that’s why I’m here.
First we need to identify what we’re looking for, which is t. So now plug 450k into equation and solve for t.
450000 = 250000e^0.013t
Now to solve this, we need to remember this rule: if you take natural log of e you can remove x from exponent. And natural log of e is 1.
Basically ln(e^x) = xln(e) = 1*x
So knowing this first we need to isolate e
450000/250000 = e^0.013t
1.8 = e^0.013t
Now take natural log of both
Ln(1.8) = ln(e^0.013t)
Ln(1.8) = 0.013t*ln(e)
Ln(1.8) = 0.013t * 1
Now solve for t
Ln(1.8)/0.013 = t
T= 45.21435 years
Now just to check our work plug that into original equation which we get:
449999.94 which is basically 500k (just with an error caused by lack of decimals)
So our final solution will be in the 45th year after about 2 and a half months it will reach 450k people.
6 0
2 years ago
Given that ABC~LMN<br> What is the length of AC?
sleet_krkn [62]

Answer:

B. 12

Step-by-step explanation:

✔️Find the value of x

The side lengths of two similar triangles are always proportional.

Given that ∆ABC ~ ∆LMN, therefore:

\frac{AB}{LM} = \frac{AC}{LN}

AB = 5

LM = 10

AC = x + 5

LN = 3x + 3

Plug in the values

\frac{5}{10} = \frac{x + 5}{3x + 3}

Cross multiply

5(3x + 3) = 10(x + 5)

15x + 15 = 10x + 50 (distributive property)

Collect like terms

15x - 10x = -15 + 50

5x = 35

Divide both sides by 5

x = 7

✔️Find AC

AC = x + 5

Plug in the value of x

AC = 7 + 5

AC = 12

6 0
3 years ago
Which line is it? help asap
ki77a [65]
The correct answer is line q
8 0
2 years ago
Read 2 more answers
Suppose a particular type of cancer has a 0.9% incidence rate. Let D be the event that a person has this type of cancer, therefo
natita [175]

Answer:

There is a 12.13% probability that the person actually does have cancer.

Step-by-step explanation:

We have these following probabilities.

A 0.9% probability of a person having cancer

A 99.1% probability of a person not having cancer.

If a person has cancer, she has a 91% probability of being diagnosticated.

If a person does not have cancer, she has a 6% probability of being diagnosticated.

The question can be formulated as the following problem:

What is the probability of B happening, knowing that A has happened.

It can be calculated by the following formula

P = \frac{P(B).P(A/B)}{P(A)}

Where P(B) is the probability of B happening, P(A/B) is the probability of A happening knowing that B happened and P(A) is the probability of A happening.

In this problem we have the following question

What is the probability that the person has cancer, given that she was diagnosticated?

So

P(B) is the probability of the person having cancer, so P(B) = 0.009

P(A/B) is the probability that the person being diagnosticated, given that she has cancer. So P(A/B) = 0.91

P(A) is the probability of the person being diagnosticated. If she has cancer, there is a 91% probability that she was diagnosticard. There is also a 6% probability of a person without cancer being diagnosticated. So

P(A) = 0.009*0.91 + 0.06*0.991 = 0.06765

What is the probability that the person actually does have cancer?

P = \frac{P(B).P(A/B)}{P(A)} = \frac{0.91*0.009}{0.0675} = 0.1213

There is a 12.13% probability that the person actually does have cancer.

3 0
3 years ago
PLEASE HELP ME ASAP ILL GIVE 100 POINTS
Airida [17]

Answer:

8(+4)

Step-by-step explanation:

6 0
3 years ago
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