Answer:
This is because even when the quality of the variable x is 0, the value of b still exists and is the starting point for y.
Step-by-step explanation:
To prove this, we start with the base form of the equation and input 0 for x.
y = mx + b
y = m(0) + b
y = 0 + b
y = b
1cm = 10mm
then 0.46cm = 0.46*10 = 4.6mm
Answer:
d, a, e, c, b
Step-by-step explanation:
9514 1404 393
Answer:
1/(3x) =(x -2)/(4x^2 +9)
Step-by-step explanation:
The denominator cannot be factored further, so the final form will be ...
A/(3x) + (Bx +C)/(4x^2 +9)
The value of this is ...
(A(4x^2 +9) +(3x)(Bx +C))/(3x(4x^2 +9))
= ((3B+4A)x^2 +3Cx +9A)/(3x(4x^2 +9))
Equating coefficients gives ...
3B+4A = 7
3C = -6 ⇒ C = -2
9A = 9 ⇒ A = 1
Using the found value of A, we find ...
3B +4 = 7 ⇒ B = 1
Then the decomposition is ...

Answer:
10.7
Step-by-step explanation:
add multiple than subtract what you multiple and add a decimal