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ElenaW [278]
3 years ago
15

In general, the larger a sample is: a. The more difficult it becomes to avoid atypical cases. b. The greater the standard deviat

ion becomes. c. The smaller the standard deviation becomes. d. The more closely it represents the population. e. The more likely it is that it will be biased.
Mathematics
1 answer:
Romashka-Z-Leto [24]3 years ago
4 0

Answer:

d

Step-by-step explanation:

Larger samples more closely resemble the population from which they come.

Think of the difference between sampling hundreds of people from a town, perhaps asking them if they've ever ordered fast food.  If you go to McDonald's and ask customers as they come out, you wouldn't expect those answers to represent the entire population of the town, right?

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Someone pls help me :c tysm if u do :))
iogann1982 [59]

Answer:13

Step-by-step explanation: Your going up on the number line.

Hope I was able to help! :)

3 0
3 years ago
Use lagrange multipliers to find the point on the plane x â 2y + 3z = 6 that is closest to the point (0, 2, 4).
Arisa [49]
The distance between a point (x,y,z) on the given plane and the point (0, 2, 4) is

\sqrt{f(x,y,z)}=\sqrt{x^2+(y-2)^2+(z-4)^2}

but since \sqrt{f(x,y,z)} and f(x,y,z) share critical points, we can instead consider the problem of optimizing f(x,y,z) subject to x-2y+3z=6.

The Lagrangian is

L(x,y,z,\lambda)=x^2+(y-2)^2+(z-4)^2+\lambda(x-2y+3z-6)

with partial derivatives (set equal to 0)

L_x=2x+\lambda=0\implies x=-\dfrac\lambda2
L_y=2(y-2)-2\lambda=0\implies y=2+\lambda
L_z=2(z-4)+3\lambda=0\implies z=4-\dfrac{3\lambda}2
L_\lambda=x-2y+3z-6=0\implies x-2y+3z=6

Solve for \lambda:

x-2y+3z=-\dfrac\lambda2-2(2+\lambda)+3\left(4-\dfrac{3\lambda}2\right)=6
\implies2=7\lambda\implies\lambda=\dfrac27

which gives the critical point

x=-\dfrac17,y=\dfrac{16}7,z=\dfrac{25}7

We can confirm that this is a minimum by checking the Hessian matrix of f(x,y,z):

\mathbf H(x,y,z)=\begin{bmatrix}f_{xx}&f_{xy}&f_{xz}\\f_{yx}&f_{yy}&f_{yz}\\f_{zx}&f_{zy}&f_{zz}\end{bmatrix}=\begin{bmatrix}2&0&0\\0&2&0\\0&0&2\end{bmatrix}

\mathbf H is positive definite (we see its determinant and the determinants of its leading principal minors are positive), which indicates that there is a minimum at this critical point.

At this point, we get a distance from (0, 2, 4) of

\sqrt{f\left(-\dfrac17,\dfrac{16}7,\dfrac{25}7\right)}=\sqrt{\dfrac27}
8 0
3 years ago
I need help anyone can help me
REY [17]
I found the answer at another website plus wanna get exposed little boys yall aint girls
5 0
3 years ago
Someone pls help me I’ll mark u brainliest
Ronch [10]
Ok I will help 10 min
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3 years ago
What does this mean 405(8) in math?
zepelin [54]
405 multiplied by 8 (: 

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4 years ago
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