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eduard
2 years ago
6

Write an inequality to match this statement: -7 is located to the right of -10. **Hint** You need to use shift and the comma but

ton or the period button to make the greater than or less than sign. * put the answer and explain please how to get it!!!!!!!
Mathematics
1 answer:
kari74 [83]2 years ago
8 0

Answer:

-7 > -10

Step-by-step explanation:

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Hi this is a challange what is.....<br><br> 700 x 500 = ?
Ksju [112]

Answer:

do 7 x 5 then add 4 zeros so its 350,000

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
Calculate the probability of each of the following events. (a) {at most three lines are in use} .72 Correct: Your answer is corr
andre [41]

Answer:

(a) The Probability that at most three lines are in use is 0.70.

(b) The Probability that fewer than three lines are in use is 0.45.

(c) The Probability that at least three lines are in use is 0.55.

(d) The Probability that between two and five lines, inclusive, are in use is 0.70.

(e) The Probability that between two and four lines, inclusive, are not in use is 0.35.

(f) The Probability that at least four lines are not in use is 0.70.

Step-by-step explanation:

<u>The complete question is: </u>A mail-order company business has six telephone lines. Let X denote the number of lines in use at a specified time. Suppose the pmf of X is as given in the accompanying table.

X    0          1       2       3          4             5               6

P(X)  0.10      0.15      0.20       0.25         0.20      0.05         0.05  

Calculate the probability of each of the following events.

(a) {at most three lines are in use}

(b) {fewer than three lines are in use}  

(c) {at least three lines are in use}  

(d) {between two and five lines, inclusive, are in use}

(e) {between two and four lines, inclusive, are not in use}

(f) {at least four lines are not in use}

Now considering the above probability distribution;

(a) The Probability that at most three lines are in use is given by = P(X \leq 3)

    P(X \leq 3) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3)

                  = 0.10 + 0.15 + 0.20 + 0.25

                  = 0.70

(b) The Probability that fewer than three lines are in use is given by = P(X < 3)

    P(X < 3) = P(X = 0) + P(X = 1) + P(X = 2)

                  = 0.10 + 0.15 + 0.20

                  = 0.45

(c) The Probability that at least three lines are in use is given by = P(X \geq 3)

    P(X \geq 3) = P(X = 3) + P(X = 4) + P(X = 5) + P(X = 6)

                  = 0.25 + 0.20 + 0.05 + 0.05

                  = 0.55

(d) The Probability that between two and five lines, inclusive, are in use is given by = P(2 \leq X \leq 5)

    P(2 \leq X \leq 5) = P(X = 2) + P(X = 3) + P(X = 4) + P(X = 5)

                         = 0.20 + 0.25 + 0.20 + 0.05

                         = 0.70

(e) The Probability that between two and four lines, inclusive, are not in use is given by = 1 - P(2 \leq X \leq 4)

    1 - P(2 \leq X \leq 4) = 1 - [P(X = 2) + P(X = 3) + P(X = 4)]

                             = 1 - [0.20 + 0.25 + 0.20]

                             = 1 - 0.65 = 0.35

(f) The Probability that at least four lines are not in use is given by = 1 - Probability that at least four lines are in use = 1 - P(X \geq 4)

    1 - P(X \geq 4) = 1 - [P(X = 4) + P(X = 5) + P(X = 6)]

                       = 1 - [0.20 + 0.05 + 0.05]

                       = 1 - 0.30 = 0.70

5 0
3 years ago
"the quotent of a number and 4" i dont wanna fail math
Zielflug [23.3K]

Answer:

N/4

Step-by-step explanation:

quotient is the same as division

since we don't know what the number is we use n as the variable

so n/4

Hope this helps

4 0
2 years ago
Estimate.Then find the differences and write it in simplest form.
Rama09 [41]
D . internal............
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3 years ago
a taxi costs 3.00 for every mile traveled, to enter a cab the is an initial charge of 4.50. write an equation where t represents
vodomira [7]

Answer:

t = 4.50 + 3.00m

3 0
2 years ago
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