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neonofarm [45]
3 years ago
11

Can someone please check my answer????

Mathematics
1 answer:
Svetlanka [38]3 years ago
8 0
Yes good job!! the one you picked is correct
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Check the picture below.

\bf \textit{Law of Cosines}\\ \quad \\&#10;c^2 = {{ a}}^2+{{ b}}^2-(2{{ a}}{{ b}})cos(C)\implies &#10;c = \sqrt{{{ a}}^2+{{ b}}^2-(2{{ a}}{{ b}})cos(C)}&#10;\\\\\\&#10;\cfrac{{{ a}}^2+{{ b}}^2-c^2}{2{{ a}}{{ b}}}=cos(C)\implies cos^{-1}\left(\cfrac{{{ a}}^2+{{ b}}^2-c^2}{2{{ a}}{{ b}}}\right)=\measuredangle C\\\\&#10;-------------------------------\\\\&#10;\begin{cases}&#10;d=10\\&#10;e=18\\&#10;f=22&#10;\end{cases}\implies cos^{-1}\left(\cfrac{{{ 18}}^2+{{ 22}}^2-10^2}{2(18)(22)}\right)=\measuredangle D

\bf \implies cos^{-1}\left(0.893\overline{93}\right)=\measuredangle D\implies 26.63^o\approx \measuredangle D

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3 years ago
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