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Anni [7]
3 years ago
10

Please Help Thank you!

Mathematics
1 answer:
zimovet [89]3 years ago
6 0

Answer:

i.7 and 5

ii.8 and 6

iii.2and 4

iv.1 and 3

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The half-life of a newly discovered radioactive element is 30 seconds. To the nearest tenth of a second, how long will it take f
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Answer:

It will take about 109.3 seconds for nine grams of the element to decay to 0.72 grams.

Step-by-step explanation:

We can write a half-life function to model our function.

A half-life function has the form:

\displaystyle A=A_0\left(\frac{1}{2}\right)^{t/d}

Where <em>A₀</em> is the initial amount, <em>t</em> is the time that has passes (in this case seconds), <em>d</em> is the half-life, and <em>A</em> is the amount after <em>t</em> seconds.

Since the half-life of the element is 30 seconds, <em>d</em> = 30. Our initial sample has nine grams, so <em>A₀</em> is 9. Substitute:

\displaystyle A=9\left(\frac{1}{2}\right)^{t/30}

We want to find the time it will take for the element to decay to 0.72 grams. So, we can let <em>A</em> = 0.72 and solve for <em>t: </em>

<em />\displaystyle 0.72=9\left(\frac{1}{2}\right)^{t/30}<em />

Divide both sides by 9:

\displaystyle 0.08=\left(\frac{1}{2}\right)^{t/30}

We can take the natural log of both sides:

\displaystyle \ln(0.08)=\ln\left(\left(\frac{1}{2}\right)^{t/30}\right)

By logarithm properties:

\displaystyle \ln(0.08)=\frac{t}{30}\ln(0.5)

Solve for <em>t: </em>

<em />\displaystyle t=\frac{30\ln(0.08)}{\ln(0.5)}\approx109.3\text{ seconds}<em />

<em />

So, it will take about 109.3 seconds for nine grams of the element to decay to 0.72 grams.

5 0
3 years ago
Please help ASAP! I need this and i am so confused!
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C. because u got to divid the numder

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Answer:

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Step-by-step explanation:

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