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Masteriza [31]
3 years ago
15

PLEASE HELP 2!/0!= 0 2 undefined

Mathematics
1 answer:
GuDViN [60]3 years ago
6 0

Answer:

2

Step-by-step explanation:

any expression divided by 1 remains the same

you can also calculate the factorial

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8TH GRADE MATH 100 POINTS+BRAINLIEST - Factor Quadratic equations- please write out the steps, explain simply, and possibly prov
Anestetic [448]

Hello,

We have : (a + b)² = a² + 2ab + b²

4x² + 20x + 25 = (2x)² + 2 × 2x × 5 + 5² = (2x + 5)² → answer B

Here, we have a = 2x and b = 5 !

6 0
1 year ago
Read 2 more answers
Peggy had three times as many quarters as nickels. She had $1.60 in all. How many nickels and how many quarters did she have?
Nonamiya [84]
0.05n + 0.25q = 1.60
q = 3n

0.05n + 0.25(3n) = 160
0.05n + 0.75n = 1.60...multiply by 100 to get rid of the decimals
5n + 75n = 160...answer D

8 0
3 years ago
Read 2 more answers
Laura has 160 pounds of green beans at her vegetable stand. If she sells 10 pounds of green beans every hour, what is the percen
Mademuasel [1]

Given:

Laura has 160 pounds of green beans at her vegetable stand.

She sells 10 pounds of green beans every hour.

To find:

The percent decrease in green beans after 3 hours.

Solution:

We have,

Beans sold in 1 hour = 10 pounds

So, Beans sold in 3 hours = 30 pounds

Decrease in green beans after 3 hours is 30 pounds.

Now,

\%\text{Decrease}=\dfrac{\text{Decrease in green beans after 3 hours }}{\text{Initial amount of green beans}}\times 100

\%\text{Decrease in green beans after 3 hours}=\dfrac{30}{160}\times 100

\%\text{Decrease in green beans after 3 hours}=\dfrac{300}{16}

\%\text{Decrease in green beans after 3 hours}=18.75\%

Therefore, the correct option is A.

7 0
3 years ago
You are testing the claim that the proportion of men who own cats is significantly different than the proportion of women who ow
Nadya [2.5K]

Answer:

Test statistic =1.30

Step-by-step explanation:

Given that you are testing the claim that the proportion of men who own cats is significantly different than the proportion of women who own cats.

                                             Men                Women            Difference

Sample size n                        60                     120

Proportion p_1, p_2              0.45                   0.35                 0.10

60 120 180

0.45 0.35 0.383333333

27 42 69

p = 0.3833

Std error for proportion difference = \bar p (1-\bar p)(\frac{1}{n_1}+\frac{1}{n_2})\\=0.3833(0.6167)(\frac{1}{60}+\frac{1}{120})\\=0.0769

Test statistic = \frac{p_1-p_2}{\bar p (1-\bar p)(\frac{1}{n_1}+\frac{1}{n_2})  }

=1.3008

=1.30

4 0
3 years ago
Need help with some questions please
iVinArrow [24]
This is the answer I think

4 0
3 years ago
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