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3 years ago

PLEASE HELP I WILL MARK!!

Mathematics

1 answer:

sesenic [268]3 years ago

5 0

Answer:

C. (16,6)

Step-by-step explanation:

Because if you count downward for 20 while you count upwards for 12, the middle of it is 16. And also do that for 4-8 then it will equal to 6

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3 + 2y = 7 what is y

lesya692 [45]

Answer:

y = 2

Step-by-step explanation:

Rearrange

2y = 7 - 3

2y = 4

make y on its own

y = 2

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3 years ago

Indicate the method you would use to prove the two Δ's . If no method applies, enter "none".

Anvisha [2.4K]

You would use HL to prove they are congruent! To prove of they were triangles you wouldn't use any of those I don't think.

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4 years ago

Point D is the in center of triangle ABC. Write an expression for the length x in terms of the three side lengths AB, AC, BC.

insens350 [35]

Answer:

$x = \frac{2(A_T) }{(AB) + (AC) + (BC)}$

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3 years ago

Write an equation in slope-intercept form of a line that contains point (-4, 6)

I am Lyosha [343]

Answer:

y = -2x - 2

Step-by-step explanation:

Please let me know if you want me to add an explanation as to why this is the answer/how I got this answer. I can definitely do that, I just wouldn’t want to write it if you don’t want me to :)

7 0

3 years ago

Pleeeeese help me as fast as you can!!!

Aleonysh [2.5K]

Answer:

A. $y=3x-10$

C. $y+6=3(x-15)$

Step-by-step explanation:

Given:

The given line is $6x+18y=5$

Express this in slope-intercept form $y=mx+b$ , where m is the slope and b is the y-intercept.

$6x+18y=5\\18y=-6x+5\\y=-\frac{6}{18}x+\frac{5}{18}\\y=-\frac{1}{3}x+\frac{5}{18}$

Therefore, the slope of the line is $m=-\frac{1}{3}$ .

Now, for perpendicular lines, the product of their slopes is equal to -1.

Let us find the slopes of each lines.

Option A:

$y=3x-10$

On comparing with the slope-intercept form, we get slope as $m_{A}=3$ .

Now, $m\times m_{A}=-\frac{1}{3}\times 3=-1$ . So, option A is perpendicular to the given line.

Option B:

For lines of the form $x=a$ , where, a is a constant, the slope is undefined. So, option B is incorrect.

Option C:

On comparing with the slope-point form, we get slope as $m_{C}=3$ .

Now, $m\times m_{C}=-\frac{1}{3}\times 3=-1$ . So, option C is perpendicular to the given line.

Option D:

$3x+9y=8\\9y=-3x+8\\y=-\frac{3}{9}x+\frac{8}{9}\\y=-\frac{1}{3}x+\frac{8}{9}$

On comparing with the slope-intercept form, we get slope as $m_{D}=-\frac{1}{3}$ .

Now, $m\times m_{D}=-\frac{1}{3}\times -\frac{1}{3}=\frac{1}{9}$ . So, option D is not perpendicular to the given line.

8 0

3 years ago