X and y represent the two students.
Teacher wants to spend at least $5 in each of x and y. That means x or y could be either equal to 5 or higher than 5.
x ≥ 5
y ≥ 5
Teacher only spends under $30. That means the sum of x and y couldn't be equal to higher than 30. It should be lower than 30.
x + y < 30
The correct answer is option D
15 x 3= 45 so therefore 45 is the length hope that help!
You have $15 and admission is $5, so you know have $10 before doing any games. If you wanted to play 12 games, you would need $10.20, which you do not have. But, if you wanted to play 11 games, then you would need $9.35, which is just under $10.
So the maximum amount of games that you could play would be 11 games.
Let's take any edge length l. The diagonal has length
. In our case it's
Answer:
B.
Step-by-step explanation:
When reflecting over the x-axis:
(x, y) (x, -y)
The y changes signs (+, -)
