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Novosadov [1.4K]
3 years ago
13

HELLO PLEASE HELP!! HAVE A GOOD DAY/NIGHT!!

Mathematics
2 answers:
il63 [147K]3 years ago
7 0

Answer:

ANSWER

A: 11

Step-by-step explanation:

hhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhh just trust me it won't let me post without and explanation

aliina [53]3 years ago
6 0

So, XZ= 7x+1 and PZ= 4x-1. To figure out XP we have to subtract those two.

(7x+1)-(4x-1)

3x-2

3(8)-2

24-2

22

XP=22

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An urn contains n white balls andm black balls. (m and n are both positive numbers.) (a) If two balls are drawn without replacem
Genrish500 [490]

DISCLAIMER: Please let me rename b and w the number of black and white balls, for the sake of readability. You can switch the variable names at any time and the ideas won't change a bit!

<h2>(a)</h2>

Case 1: both balls are white.

At the beginning we have b+w balls. We want to pick a white one, so we have a probability of \frac{w}{b+w} of picking a white one.

If this happens, we're left with w-1 white balls and still b black balls, for a total of b+w-1 balls. So, now, the probability of picking a white ball is

\dfrac{w-1}{b+w-1}

The probability of the two events happening one after the other is the product of the probabilities, so you pick two whites with probability

\dfrac{w}{b+w}\cdot \dfrac{w-1}{b+w-1}=\dfrac{w(w-1)}{(b+w)(b+w-1)}

Case 2: both balls are black

The exact same logic leads to a probability of

\dfrac{b}{b+w}\cdot \dfrac{b-1}{b+w-1}=\dfrac{b(b-1)}{(b+w)(b+w-1)}

These two events are mutually exclusive (we either pick two whites or two blacks!), so the total probability of picking two balls of the same colour is

\dfrac{w(w-1)}{(b+w)(b+w-1)}+\dfrac{b(b-1)}{(b+w)(b+w-1)}=\dfrac{w(w-1)+b(b-1)}{(b+w)(b+w-1)}

<h2>(b)</h2>

Case 1: both balls are white.

In this case, nothing changes between the two picks. So, you have a probability of \frac{w}{b+w} of picking a white ball with the first pick, and the same probability of picking a white ball with the second pick. Similarly, you have a probability \frac{b}{b+w} of picking a black ball with both picks.

This leads to an overall probability of

\left(\dfrac{w}{b+w}\right)^2+\left(\dfrac{b}{b+w}\right)^2 = \dfrac{w^2+b^2}{(b+w)^2}

Of picking two balls of the same colour.

<h2>(c)</h2>

We want to prove that

\dfrac{w^2+b^2}{(b+w)^2}\geq \dfrac{w(w-1)+b(b-1)}{(b+w)(b+w-1)}

Expading all squares and products, this translates to

\dfrac{w^2+b^2}{b^2+2bw+w^2}\geq \dfrac{w^2+b^2-b-w}{b^2+2bw+w^2-b-w}

As you can see, this inequality comes in the form

\dfrac{x}{y}\geq \dfrac{x-k}{y-k}

With x and y greater than k. This inequality is true whenever the numerator is smaller than the denominator:

\dfrac{x}{y}\geq \dfrac{x-k}{y-k} \iff xy-kx \geq xy-ky \iff -kx\geq -ky \iff x\leq y

And this is our case, because in our case we have

  1. x=b^2+w^2
  2. y=b^2+w^2+2bw so, y has an extra piece and it is larger
  3. k=b+w which ensures that k<x (and thus k<y), because b and w are integers, and so b<b^2 and w<w^2

4 0
3 years ago
What is the force of gravity (in Newtons) acting between the Earth and a 100-kg person who is on board the International Space S
ratelena [41]

Answer:

f_{G}=317877.55 N = 317.8 kN

Step-by-step explanation:

f_{G}= (G*m_{1}*m_{2})/r^{2}  \\Where:\\f_{G}= force  of  gravity\\G=gravitational constant= 6.6x10^{-11}m^{3}kg^{-1}s^{-2}\\ m_{1}= earth mass = 5.9x10^{24}kg\\m_{2}=person mass = 100kg\\r= distance between the bodies=350km= 350 000 m

5 0
3 years ago
The width of a rectangle is 21 meters. The area is 609 square meters. What is the length?
VLD [36.1K]

Step-by-step explanation:

Remember Area = length X Width

7 0
3 years ago
I need help i dot get it.
gayaneshka [121]

Answer:

the answer is about 8 cuz the answer shows 7.12 if you divide mentally

6 0
2 years ago
Read 2 more answers
6) 9(x - 1)+ 4x<br><br>what's the answer​
svet-max [94.6K]

Answer:

13x-9

Step-by-step explanation:

9×(x - 1)

9x - 9 +4x

collect like terms, 9x+4x=13x

4 0
3 years ago
Read 2 more answers
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