The line segment AB with endpoints (-10,0) and (6,8). The equation of the line segment is x-2y+10=0.
Given that,
The line segment AB with endpoints (-10,0) and (6,8).
We have to find the equation of the line segment.
The equation of the line formula is y-y₁=m(x-x₁).
Here we don't know the m value that is nothing but slope of the line.
First we have to find the slope of the line segment.
Slope of the line m=![\frac{y_{2} -y_{1} }{x_{2} -x_{1} }](https://tex.z-dn.net/?f=%5Cfrac%7By_%7B2%7D%20-y_%7B1%7D%20%7D%7Bx_%7B2%7D%20-x_%7B1%7D%20%7D)
m=(8-0)/(6+10)
m=8/16
m=1/2
Now,
We know the equation of line is y-y₁=m(x-x₁)
y-0=1/2(x+10)
2y=x+10
x-2y+10=0
Therefore, The equation of the line segment is x-2y+10=0.
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Answer:
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Step-by-step explanation:
have a great day :)
Answer:
x = - 7, x = 3
Step-by-step explanation:
To find the zeros let y = 0, that is
- x² - 4x + 21 = 0 ( multiply through by - 1 )
x² + 4x - 21 = 0
Consider the factors of the constant term (- 21) which sum to give the coefficient of the x- term (+ 4)
The factors are + 7 and - 3, since
7 × - 3 = - 21 and 7 - 3 = + 4, thus
(x + 7)(x - 3) = 0
Equate each factor to zero and solve for x
x + 7 = 0 ⇒ x = - 7
x - 3 = 0 ⇒ x = 3