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drek231 [11]
3 years ago
9

Tell whether the ordered pair is a solution to the system of linear equations. 1 point

Mathematics
1 answer:
Nataly_w [17]3 years ago
3 0

Answer:

Tell whether the ordered pair is a solution to the system of linear equations. 1 point

(-2,-1); 2x – 4y= -8

6x + 5y = -7

No

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The growth of a group of bacteria is modeled by the function f(x) =10x. Identify the key features of the model.
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The Y INTERCEPT is x the range is 10
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I don’t know how to solve this
Lady_Fox [76]

Answer:

\theta =2\pi k,\ \ k\in Z\ \\\text{or}\ \\\theta=-\dfrac{2\pi}{3}+2\pi k,\ \ k\in Z

Step-by-step explanation:

Given:

\cos \theta-\sqrt{3}\sin \theta=1

Divide this equation by 2:

\dfrac{1}{2}\cos \theta-\dfrac{\sqrt{3}}{2}\sin \theta=\dfrac{1}{2}

Note that

\cos \dfrac{\pi }{3}=\dfrac{1}{2}\\ \\\sin \dfrac{\pi }{3}=\dfrac{\sqrt{3}}{2}

So, the previous equation is

\cos \dfrac{\pi}{3}\cdot \cos \theta-\sin \dfrac{\pi}{3}\cdot \sin \theta=\dfrac{1}{2}

Remind that

\cos x\cos y-\sin x\sin y=\cos (x+y),

then

\cos \left(\dfrac{\pi}{3}+\theta\right)=\dfrac{1}{2}

The solution of this equation is

\dfrac{\pi}{3}+\theta=\pm \arccos \dfrac{1}{2}+2\pi k,\ \ k\in Z\\ \\\dfrac{\pi}{3}+\theta=\pm \dfrac{\pi}{3}+2\pi k,\ \ k\in Z\\ \\\theta =2\pi k,\ \ k\in Z\ \text{or}\ \theta=-\dfrac{2\pi}{3}+2\pi k,\ \ k\in Z

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4 years ago
What are the measures of the angles in triangle ABC?
VMariaS [17]

Complete question :

A right triangle has side lengths AC = 7 inches, BC = 24 inches, and AB = 25 inches.

What are the measures of the angles in triangle ABC?

a) m∠A ≈ 46.2°, m∠B ≈ 43.8°, m∠C ≈ 90°

b) m∠A ≈ 73.0°, m∠B ≈ 17.0°, m∠C ≈ 90°

c) m∠A ≈ 73.7°, m∠B ≈ 16.3°, m∠C ≈ 90°

d) m∠A ≈ 74.4°, m∠B ≈ 15.6°, m∠C ≈ 90°

Answer:

c) m∠A ≈ 73.7°, m∠B ≈ 16.3°, m∠C ≈ 90°

Step-by-step explanation:

Given:

Length AC = 7 inches

Length BC = 24 inches

Length AB = 25 inches

Since it is a right angle triangle,

m∠C = 90°

To find the measures of the angle in ∠A and ∠B, we have :

For ∠A:

SinA = \frac{BC}{AB}

SinA = \frac{24}{25}

SinA = 0.96

A = Sin^-^1 = 0.96

∠A = 73.7°

For ∠B:

SinB = \frac{AC}{AB}

SinB = \frac{7}{25}

SinB = 0.28

B = Sin^-^1 = 0.96

∠B = 16.26 ≈ 16.3°

Therefore,

m∠A = 73.7°

m∠B = 16.3°

m∠C = 90°

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3 years ago
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devlian [24]
2,330.96 would be rounded answer
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3 years ago
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