The Cube Root Of -343 is ( -7)
The probability any one system works is 0.99
So the probability of any one system failing is 1-0.99 = 0.01, so basically a 1% chance of failure for any one system
Multiply out the value 0.01 with itself four times
0.01*0.01*0.01*0.01 = 0.000 000 01
I'm using spaces to make the number more readable
So the probability of all four systems failing is 0.00000001
Subtract this value from 1 to get
1 - 0.00000001 = 0.99999999
The answer is 0.99999999 which is what we'd expect. The probability of at least one of the systems working is very very close to 1 (aka 100%)
Answer:
q= -1x
coordinates of p are .5, 2
Step-by-step explanation:
I apologize if I'm wrong love
Answer:
a) strong negative linear correlation.
b) Weak or no linear correlation.
c) strong positive linear correlation.
Step-by-step explanation:
The correlation coefficient r measures the strength and direction (positive or negative) of two variables. The correlation coefficient r is always between -1 and 1. When the coefficient r is negative then the direction of the correlation is downhill (negative) and when it's positive then it's an uphill correlation (positive). Similarly, as the coefficient is closer to -1 or 1 the correlation is stronger, with zero being a non linear relationship.
Now back to the question:
a) Near -1: as we said before, this means an strong negative (-1) linear correlation.
b) Near 0: weak or no linear correlation (we cannot say if its positive or negative because we don't know it it's near zero from the right (positive numbers) or the left (negative numbers)
c) Near 1: strong positive (close to +1) linear correlation
Answer:

Step-by-step explanation:
Given
Poisson Distribution;
Average rent in a week = 2.3
Required
Determine the probability of renting no more than 1 apartment
A Poisson distribution is given as;

Where y represents λ (average)
y = 2.3
<em>Probability of renting no more than 1 apartment = Probability of renting no apartment + Probability of renting 1 apartment</em>
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Using probability notations;

Solving for P(X = 0) [substitute 0 for x and 2.3 for y]




Solving for P(X = 1) [substitute 1 for x and 2.3 for y]









Hence, the required probability is 0.331