To find the surface are, we can add up the area of all of the sides.
Top:
4in x 9in = 36in^2
Bottom:
<span>4in x 9in = 36in^2
</span>
Front:
5in x 9 in = 45in^2
Back:
<span>5in x 9 in = 45in^2
</span>
Right:
4in x 5in = 20in^2
Left:
<span>4in x 5in = 20in^2
</span>
Adding them all together:
36+36+45+45+20+20 = 202in^2
The surface area of the prism is 1. 202 in^2
Answer: i would say A and D but i'm not sure of the others
<h3>
Answer: Choice A</h3>
Side = 5 ft, side = 15 ft, side = 3 ft
Explanation:
The two sides 5 ft and 3 ft add to 5+3 = 8 ft which is not larger than the 15 ft side. This is exactly why a triangle is not possible here.
If we want a triangle to happen, then adding any two sides must be larger than the third side.
If we want a triangle with sides a,b,c, then we need the following to be true
Refer to the triangle inequality theorem for more information.
![P\cup Q](https://tex.z-dn.net/?f=P%5Ccup%20Q)
would be the set referring to everything within the sets
![P](https://tex.z-dn.net/?f=P)
and
![Q](https://tex.z-dn.net/?f=Q)
. Their complement,
![(P\cup Q)^C](https://tex.z-dn.net/?f=%28P%5Ccup%20Q%29%5EC)
, would then be everything else outside the union. Intersecting that set with
![S](https://tex.z-dn.net/?f=S)
will give the shaded region,
![(P\cup Q)^C\cap S](https://tex.z-dn.net/?f=%28P%5Ccup%20Q%29%5EC%5Ccap%20S)
.