The midsegment of a trapezoid is the segment connecting the midpoints of the two non-parallel sides. In trapezoid below, segment P Q is the midsegment. The length of the midsegment of trapezoid is half the sum of the lengths of the two parallel sides. In the figure above: P Q = A B + C D 2.
It's a six sided polygon. For any polygon the external angles add to 360 degrees. The internal angles shown are the supplements of the external angles. We have
(180 - θ₁) + (180 - θ₂) + ... + (180 - θ₆) = 360
6(180) - 360 = θ₁ + θ₂ + θ₃ + θ₄ + θ₅ + θ₆
720 = θ₁ + θ₂ + θ₃ + θ₄ + θ₅ + θ₆
The six angles add up to 720 degrees, and five of them add to
126+101+135+147+96=605
So y = 720 - 605 = 115
The degree sign is external to y so not part of the answer:
Answer: 115
Answer:
p = 4√5
Step-by-step explanation:
To solve for P, we can use the Pythagorean theorem.
a²+b²=c²
(8)²+(p)²=12²
64+p²=144
p²=80
√p=√80
p = 4√5
Yes because they both give you an x =2 and a y=-4