Answer: a. The table below shows the level of Z- Med in the patient's body
nn y = f(nn)
0 16
2 8
4 4
6 2
7 1
8 0.5
10 0.25
14 0.125
16 0.0625
18 0.03125
20 0.015625
… …
nn f(nn -1)/2
b. The formula to model the half-life of Z-Med for nn days is given by
c. The radioactive material from Z-Med is left in the patient’s body after 20 days of receiving the medicine is 0.0156 mCi (4 d.p)
Step-by-step explanation:
a. To make the table one has to have a <u>left hand column</u> with nn, which represents the number of days and a <u>right hand column</u> with y, <em>which represents the residual radioactive material as per that number of days</em>. It should be noted that the table has an interval of two days because that is the half-life of the drug. And the residual drug reduces by half the quantity from the previous interval.
b. To get the formula for the model, one has to understand that this is an exponential type model which has the general form of .
So, to get this formula we should take two intervals from the table, preferably (0,16) and (2,8)
Therefore, a = 16
Therefore, b = 0.7071
Now applying these constants to the formula we are trying to derive
c. To find the quantity of radioactive material left in the patient's body after 20 days just substitute nn with 20
y = 0.015622003
y = 0.0156 mCi (4 d.p)