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Fudgin [204]
3 years ago
7

On Monday, the coldest temperature outside was $2$ degrees Fahrenheit. On Tuesday, Ms. Perkins tells her students that the colde

st temperature outside has an absolute value of $4$ degrees.
Rachel says that Tuesday’s coldest temperature could be greater than Monday’s coldest temperature.
Tom says that Tuesday’s coldest temperature could be less than Monday’s coldest temperature.
State whether each student’s statement is true or false, and justify your answers.

Respond in the space provided
Mathematics
2 answers:
NISA [10]3 years ago
8 0

Answer:  Rachel is correct the coldest temperature could be greater than Mondays.            Step-by-step explanation: Because 2 degrees Fahrenheit is less than 4 degrees which makes Rachel right.

expeople1 [14]3 years ago
7 0

Answer:

23

Step-by-step explanation:

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Solution we have
The triangular prism in which
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then, we know that,
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A group of 80 ants went to collect some honey. 1/2 lost their way and 1/4 got eaten by a passing anteater. How many ants came ba
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23

Step-by-step explanation:

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3 years ago
Write down the inequality described by "half of x is no more than three", and solve for x.
emmainna [20.7K]

Answer:

Inequality: \frac{x}{2} \leq 3

Solved: x\leq 6

Step-by-step explanation:

\frac{x}{2} \leq 3

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7 0
3 years ago
Customers can pick their own apples at wells orchards . They pay $6 to enter the orchard and $2 per pound for the apples they pi
Karo-lina-s [1.5K]
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4 0
3 years ago
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What can be said about the discriminant of the graph below?
san4es73 [151]

Answer:

C. The discriminant is negative, so there are no solutions.

Step-by-step explanation:

We see that the given figure is a graph of a parabola.

The equation of the given parabola is y=(x-3)^{2}+1.

Simplifying the equation in quadratic form, we get,

The equation is y=(x-3)^{2}+1 i.e. y=x^{2}+9-6x+1 i.e. y=x^{2}-6x+10.

We know that the discriminant of a quadratic equation ax^{2}+bx+c=0 is given by D=b^{2}-4ac

So, from the equation x^{2}-6x+10=0, we have,

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Hence, as the discriminant is negative, there are no solutions.

7 0
3 years ago
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