Answer:
Step-by-step explanation:
total weight is 4 tons.
ratio of weight of truck to weight of coal is 7:5....added = 12
so 7/12 of the total weight is the truck's
and 5/12 of the total weight is the coal
7/12 of 4 tons = 7/12 * 4 = 28/12 = 2 1/3 tons <== weight of truck
5/12 of 4 tons = 5/12 * 4 = 20/12 = 1 2/3 tons <== weight of coal
Ok so I uploaded the picture of how to do the promblem step by step so you know :)
Answer:
Step-by-step explanation:
domain:A
range: D
Answer:
P=41.72
Step-by-step explanation:
S=ACxDB/2
81.7=8.6xDB/2
81.7=4.3xDB|:4.3
19(mm)=DB
DO=19/2=9.5
OC=8.6/2=4.3
(O is the center of the rhombus, where two diagonals meet)
a²+b²=c² (DO²+OC²=DC²)
9.5²+4.3²=c²
90.25+18,49=c²
√108,74=√c²
c≈10.43
P=4c
P=4x10.43
P=41.72
Hope it helps:)