3 years ago

Is 2000 ib greater than 1 T

Mathematics

1 answer:

marin [14]3 years ago

3 0

Answer:

no its =

Step-by-step explanation:

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6.25t plus 8 = 12.5t plus 13

givi [52]

6.25t + 8 = 12.5t + 13

Subtract 8 from both sides

6.25t = 12.5t +5

Subtract 12.5t from both sides

-6.25t = 5

Divide -6.25 by both sides

t = 0.8

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4 years ago

A bag has sixteen marbles in it. There are four of each color. There

Ne4ueva [31]

Answer: 25 percent

Step-by-step explanation:

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3 years ago

Factor the expression completely over the complex numbers. X3+5x2+9x+45

shepuryov [24]

$x^3+5x^2+9x+45=x^2(x+5)+9(x+5)=(x+5)(x^2+9)=(*)\\\\x^2+9=x^2+3^2=x^2-(-1)(3^2)=x^2-(i^2)(3^2)=x^2-(3i)^2\\\\i=\sqrt{-1}\to i^2=-1\\\\(*)=(x+5)[x^2-(3i)^2]=(x+5)(x-3i)(x+3i)\\\\Used:\ a^2-b^2=(a-b)(a+b)\\\\Answer:\ x^3+5x^2+9x+45=(x+5)(x-3i)(x+3i)$

4 0

3 years ago

Read 2 more answers

Counting by 8s<br> Homework

galben [10]

Answer:

8,16,24,32,40,48,56,64,72,80,88,96

Step-by-step explanation:

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3 years ago

If copies of all your computer data are stored on four independent hard disk drives, what is the probability that during a yea

Natasha2012 [34]

Answer:

$P(Atleast\ 1) = 0.9999992$

Step-by-step explanation:

Given

$p = 3\%$ --- rate of hard disk drives failure

$n = 4$ --- number of hard disk drives

<em>See comment for complete question</em>

Required

$P(Atleast\ 1)$

First, calculate the probability that the none of the 4 selected is working;

$P(none) = p^4$

$P(none) = (3\%)^4$

$P(none) = (0.03)^4$

Using the complement rule, the probability that at least 1 is working is:

$P(Atleast\ 1) = 1 - P(none)$

This gives:

$P(Atleast\ 1) = 1 - 0.03^4$

$P(Atleast\ 1) = 0.9999992$

5 0

3 years ago