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cestrela7 [59]
3 years ago
10

In the formula that gives the circumference of a circle, which quantity is multiplied by 2π ?​

Mathematics
1 answer:
N76 [4]3 years ago
4 0

Answer:

Radius

Step-by-step explanation:

Radius is multiplied by 2pi

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Find the value of x when y = 16.<br> y = -5x + 4<br>x = ?​
spayn [35]

Answer:

- 12/5

Step-by-step explanation:

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What is -3/4x + 1/2y - 9/4x - 11/2y in simplest form?
Allushta [10]

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HELP DUE IN 15 MINS!
boyakko [2]

Answer:

r = 2\sqrt{5}

(x - 3)^{2} + ( y - 2)^{2} = 20

Is this a live test question or a homework question?

Step-by-step explanation:

the radius is the distance between (3, 2) and (5, -2)

r^{2} = {(3 - 5)^{2} + (2 + 2)^{2}  }

    =  (-2)^{2} + 4^{2}

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Equation of circle:   (x - 3)^{2} + ( y - 2)^{2} = 20

8 0
3 years ago
Read 2 more answers
Compute the value of the following improper integral if it converges. If it diverges, enter INF if it diverges to infinity, MINF
Phoenix [80]

Answer:

INF for first while D for second

Step-by-step explanation:

Ok I think I read that integral with lower limit 1 and upper limit infinity

where the integrand is ln(x)*x^2

integrate(ln(x)*x^2)

=x^3/3 *ln(x)- integrate(x^3/3 *1/x)

Let's simplify

=x^3/3 *ln(x)-integrate(x^2/3)

=x^3/3*ln(x)-1/3*x^3/3

=x^3/3* ln(x)-x^3/9+C

Now apply the limits of integration where z goes to infinity

[z^3/3*ln(z)-z^3/9]-[1^3/3*ln(1)-1^3/9]

[z^3/3*ln(z)-z^3/9]- (1/9)

focuse on the part involving z... for now

z^3/9[ 3ln(z)-1]

Both parts are getting positive large for positive large values of z

So the integral diverges to infinity (INF)

By the integral test... the sum also diverges (D)

3 0
3 years ago
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