Answer:
- 12/5
Step-by-step explanation:
Answer: -3x-5y
Step-by-step explanation:
Answer:
r = 

Is this a live test question or a homework question?
Step-by-step explanation:
the radius is the distance between (3, 2) and (5, -2)
= 
= 
= 4 + 16 = 20
r = 
Equation of circle: 
Answer:
INF for first while D for second
Step-by-step explanation:
Ok I think I read that integral with lower limit 1 and upper limit infinity
where the integrand is ln(x)*x^2
integrate(ln(x)*x^2)
=x^3/3 *ln(x)- integrate(x^3/3 *1/x)
Let's simplify
=x^3/3 *ln(x)-integrate(x^2/3)
=x^3/3*ln(x)-1/3*x^3/3
=x^3/3* ln(x)-x^3/9+C
Now apply the limits of integration where z goes to infinity
[z^3/3*ln(z)-z^3/9]-[1^3/3*ln(1)-1^3/9]
[z^3/3*ln(z)-z^3/9]- (1/9)
focuse on the part involving z... for now
z^3/9[ 3ln(z)-1]
Both parts are getting positive large for positive large values of z
So the integral diverges to infinity (INF)
By the integral test... the sum also diverges (D)