Answer:
Step-by-step explanation:
Data given
20 13 21 18 19 22 19 15 12 12 18 21
We can calculate the sample mean and deviation with the following formulas:
And we got:
represent the sample mean
population mean (variable of interest)
s=3.61 represent the sample standard deviation
n=12 represent the sample size
Confidence interval
The confidence interval for the mean is given by the following formula:
(1)
The degrees of freedom are given by:
Since the Confidence is 0.90 or 90%, the significance is and , the critical value would be given by
Now we have everything in order to replace into formula (1):
The function is f(x) = [2/3] [6^x]
It is an exponential function whose range is all the positive values. This is, for any value of x that exponential function yields a value that is greater than 0. The graph never crosses the x-axis.
When you reflect the function over the x-axis, you flip the graph over x, and you can see that the range of the new fucntion iis all the negative values, this is all the real numbers less than zero.
Answer: all the real numbers less than zero.
Answer:
The 99% confidence interval for the proportion of the population who are obese is (0.25, 0.282)
Step-by-step explanation:
In a sample with a number n of people surveyed with a probability of a success of , and a confidence level of , we have the following confidence interval of proportions.
In which
z is the zscore that has a pvalue of .
For this problem, we have that:
99% confidence level
So , z is the value of Z that has a pvalue of , so .
The lower limit of this interval is:
The upper limit of this interval is:
The 99% confidence interval for the proportion of the population who are obese is (0.25, 0.282)