Question

F(x)-mx+ b, f(-2)=3 and f(4)=1 , what is the value of m and b

Answer 1

Answer: $m=\dfrac{-1}{3}, b=\dfrac{7}{3}$

Step-by-step explanation:

Given

Function is  $f(x)=mx+b$

$f(-2)=3$

$\therefore 3=m(-2)+b\\\Rightarrow b-2m=3\quad \ldots(i)$

$f(4)=1\\\therefore 1=4m+b\quad \ldots(ii)$

from (i) and (ii) we get

$m=\dfrac{-1}{3}, b=\dfrac{7}{3}$