F(x)-mx+ b, f(-2)=3 and f(4)=1 , what is the value of m and b

Mathematics

1 answer:

NeX [460]2 years ago

3 0

Answer: $m=\dfrac{-1}{3}, b=\dfrac{7}{3}$

Step-by-step explanation:

Given

Function is $f(x)=mx+b$

$f(-2)=3$

$\therefore 3=m(-2)+b\\\Rightarrow b-2m=3\quad \ldots(i)$

$f(4)=1\\\therefore 1=4m+b\quad \ldots(ii)$

from (i) and (ii) we get

$m=\dfrac{-1}{3}, b=\dfrac{7}{3}$

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4 0

2 years ago

Read 2 more answers

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nataly862011 [7]

Answer:

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