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Maksim231197 [3]
3 years ago
8

What is a equivalent fraction for The ratio of rainy days to sunny days is 5/7? (ratio)

Mathematics
2 answers:
amid [387]3 years ago
5 0

Answer: 10/14

Step-by-step explanation:

gtnhenbr [62]3 years ago
3 0

Answer:

15/21 or 15:21

Step-by-step explanation:

if you do 5 times 3 you get 15 and 7 times 3 you get 21

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F(x) = 3x ^ 2 + 2x + 10
Cloud [144]

Answer:

No x-intercept (zero)

f(0)=10

Step-by-step explanation:

8 0
3 years ago
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Larry was born on June 7, 1962. His little sister was born thirteen years and three days later. When was his sister born?
Viefleur [7K]

Answer:

The answer is B

Step-by-step explanation:

2021 - 1962 =59

59-13=46

2021-46=1975

Then 7+3=10

3 0
3 years ago
Which expressions below are equivalent to 43c+513 ? Select all that apply. □ A. 13(4c+16) □ B. 43(c+4) □ C. 13(33c+5) □ D. 23(2c
Viktor [21]
It's A because you need to distribute
4 0
3 years ago
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3(b+1)=4b-1 I need help
steposvetlana [31]

Answer:

3b + 3 = 4b - 1

3= b - 1

b= 4 is the solution

3 0
3 years ago
A population of protozoa develops with a constant relative growth rate of 0.4964 per member per day. On day zero the population
vodka [1.7K]

Answer:

The population size after eight days is about 265

Step-by-step explanation:

This is an example of an exponential growth model. A quantity <em>y</em> that grows or decays at a rate proportional to its size fits in an equation of the form

\frac{dy}{dt}=ky

where k is a positive constant. Its solutions have the form

y=y_{0}e^{kt},

where y_{0} =y(0) is the initial value of y.

The population size can be calculated by using the below formula:

P(t)=P(0)e^{kt} where P(0) is the population on day zero.

Let t be the time in days,

We know from the information given that:

  • k = 0.4964 per member per day and
  • The day zero (t = 0) the population size is 5 (P(0) = 5)

To find the population size after eight days

Substitute P(0) = 5, k=0.4964 in P(t)=P(0)e^{kt}

Then

P(t)=5e^{0.4964\cdot t}

Now we calculate P(t) when t = 8 days

P(8) = 5e^{0.4964\cdot 8}\\P(8) = 5e^{3.9712}\\e^{3.9712}=53.04815\dots \\P(8) = 5 \cdot 53.04815\dots\\P(8) = 265.24075\dots \approx 265

Therefore the population size after eight days is about 265

8 0
3 years ago
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